问题
I'm used to debug my code using ghci. Often, something like this happens (not so obvious, of course):
ghci> let f@(_:x) = 0:1:zipWith(+)f x
ghci> length f
Then, nothing happens for some time, and if I don't react fast enough, ghci has eaten maybe 2 GB of RAM, causing my system to freeze. If it's too late, the only way to solve this problem is [ALT] + [PRINT] + [K].
My question: Is there an easy way to limit the memory, which can be consumed by ghci to, let's say 1 GB? If limit is exceed, the calculation should ve aborted or ghci should be killed.
回答1:
A platform independant way to accomplish this is to supply the -M option as on option to the Haskell runtime like this
ghci +RTS -M1m
see the GHC documentation’s page on how to control the RTS (runtime system) for details.
The ghci output now looks like:
>ghci +RTS -M10m
GHCi, version 6.12.3: http://www.haskell.org/ghc/ :? for help
Loading package ghc-prim ... linking ... done.
Loading package integer-gmp ... linking ... done.
Loading package base ... linking ... done.
Loading package ffi-1.0 ... linking ... done.
Prelude> let f@(_:x) = 0:1:zipWith(+)f x
Prelude> length f
Heap exhausted;
Current maximum heap size is 10485760 bytes (10 MB);
use `+RTS -M<size>' to increase it.
回答2:
Running it under a shell with ulimit -m set is a fairly easy way. If you want to run with some limit on a regular basis, you can create a wrapper script that does ulimit before running ghci.
来源：https://stackoverflow.com/questions/3766656/is-there-a-way-to-limit-the-memory-ghci-can-have