问题
import logging
logging.basicConfig(level=logging.DEBUG, format='%(asctime)s %(levelname)s %(message)s', datefmt='%H:%M:%S')
logging.info('hello')
logging.warning('\n new hello')
11:15:01 INFO hello
11:16:49 WARNING
new hello
Because the log is crowded, I want to explicitly insert a newline before asctime and levelname. Is this possible without modifying format?
I looked into logging module and googled a bit and could not find a viable way.
回答1:
I have two solutions, the first is very easy, but the output is not very clean. The second method will produce the exact output you want, but it is a little more involved.
Method 1
To produce a blank line, just log an empty string with a new line:
import logging
logging.basicConfig(level=logging.DEBUG, format='%(asctime)s %(levelname)s %(message)s', datefmt='%H:%M:%S')
logging.info('hello')
logging.info('\n')
logging.warning('new hello')
The output will have an empty info line, which is not very clean:
16:07:26 INFO hello
16:07:26 INFO16:07:26 WARNING new hello
Method 2
In this method, I created two different handlers. The console_handler which I use most of the time. When I need a new line, I switch to a second handler, blank_handler.
import logging
import types
def log_newline(self, how_many_lines=1):
# Switch handler, output a blank line
self.removeHandler(self.console_handler)
self.addHandler(self.blank_handler)
for i in range(how_many_lines):
self.info('')
# Switch back
self.removeHandler(self.blank_handler)
self.addHandler(self.console_handler)
def create_logger():
# Create a handler
console_handler = logging.StreamHandler()
console_handler.setLevel(logging.DEBUG)
console_handler.setFormatter(logging.Formatter(fmt="%(name)s %(levelname)-8s: %(message)s"))
# Create a "blank line" handler
blank_handler = logging.StreamHandler()
blank_handler.setLevel(logging.DEBUG)
blank_handler.setFormatter(logging.Formatter(fmt=''))
# Create a logger, with the previously-defined handler
logger = logging.getLogger('logging_test')
logger.setLevel(logging.DEBUG)
logger.addHandler(console_handler)
# Save some data and add a method to logger object
logger.console_handler = console_handler
logger.blank_handler = blank_handler
logger.newline = types.MethodType(log_newline, logger)
return logger
if __name__ == '__main__':
logger = create_logger()
logger.info('Start reading database')
logger.info('Updating records ...')
logger.newline()
logger.info('Finish updating records')
The output is what you want to see:
logging_test INFO : Start reading database
logging_test INFO : Updating records ...
logging_test INFO : Finish updating records
Discussion
- If you can put up with the less-than-perfect output, method 1 is the way to go. It has the advantage of being simple, least amount of effort.
- The second method does the job correctly, but it is a little involved. It creates two different handlers and switch them in order to achieve your goal.
- Another disadvantage of using method 2 is you have to change your code by searching for
loggingand replacing them withlogger. You must take care replacing only relevant parts and leave such text aslogging.DEBUGin tact.
回答2:
Could you not add the newline after the first hello? i.e.
logging.basicConfig(level=logging.DEBUG, format='%(asctime)s %(levelname)s %(message)s', datefmt='%H:%M:%S')
logging.info('hello\n')
logging.info('new hello')
Which will output
2014-08-06 11:37:24,061 INFO : hello
2014-08-06 11:37:24,061 INFO : new hello
回答3:
Use a custom Formatter which uses different format strings at different times. You can't do this using basicConfig() - you'll have to use other parts of the logging API.
class MyFormatter(logging.Formatter):
def format(self, record):
# set self._fmt to value with or without newline,
# as per your decision criteria
# self._fmt = ...
return super(MyFormatter, self).format(record)
Or, you can call the super method, then modify the string to insert a newline before returning it (in case it's dependent on line length, say).
回答4:
Easiest way to insert newlines that I figured out:
logging.basicConfig(level=logging.DEBUG, format='%(asctime)s %(levelname)s\n\r%(message)s', datefmt='%H:%M:%S')
logging.info('hello')
logging.info('new hello')
11:50:32 INFO
hello
11:50:32 INFO
new hello
回答5:
If you are just looking to output some debug code in development then you may not want to spend time on this. The 5 second fix is this;
str = "\n\n\n"
log.getLogger().debug(str)
where the logger is the standard python logger
回答6:
Something like this. Add \n into you logging.basicConfig between asctime and levelname
>>> logging.basicConfig(level=logging.DEBUG, format='%(asctime)s\n %(levelname)s %(message)s',datefmt='%H:%M:%S')
回答7:
As an alternative to Hai Vu's Method 2 you could as well reset the handler's Formatter every time you want to log a new line:
import logging
import types
def log_newline(self, how_many_lines=1):
# Switch formatter, output a blank line
self.handler.setFormatter(self.blank_formatter)
for i in range(how_many_lines):
self.info('')
# Switch back
self.handler.setFormatter(self.formatter)
def create_logger():
# Create a handler
handler = logging.StreamHandler()
handler.setLevel(logging.DEBUG)
formatter = logging.Formatter(fmt="%(name)s %(levelname)-8s: %(message)s")
blank_formatter = logging.Formatter(fmt="")
handler.setFormatter(formatter)
# Create a logger, with the previously-defined handler
logger = logging.getLogger('logging_test')
logger.setLevel(logging.DEBUG)
logger.addHandler(handler)
# Save some data and add a method to logger object
logger.handler = handler
logger.formatter = formatter
logger.blank_formatter = blank_formatter
logger.newline = types.MethodType(log_newline, logger)
return logger
if __name__ == '__main__':
logger = create_logger()
logger.info('Start reading database')
logger.info('Updating records ...')
logger.newline()
logger.info('Finish updating records')
Output
logging_test INFO : Start reading database
logging_test INFO : Updating records ...
logging_test INFO : Finish updating records
The advantage of this is that you have a single handler. For example you can define a FileHandler's mode-attribute to write, if you wanted to clean your log-file on every new run of your program.
回答8:
Following up on Vinay Salip's helpful answer (below), I did it this way (I'm using the python3 superclass convention, but super(MyFormatter, self) works just as well) ...
class MyFormatter(logging.Formatter):
def format(self, record):
return super().format(record).replace(r'\n', '\n')
Then, I can embed newlines as follows:
logging.info('Message\\n\\n\\n\\nOther stuff')
or
logging.info(r'Message\n\n\n\nOther stuff')
回答9:
If you use FileHandler or descendants thereof, these two functions may help. An added benefit is that all FileHandler type handlers attached to the logger should get the newline.
def getAllLoggerFilenames(logger):
""" Returns array of all log filenames attached to the logger. """
logFiles = [];
parent = logger.__dict__['parent'];
if parent.__class__.__name__ == 'RootLogger':
for h in logger.__dict__['handlers']:
if h.baseFilename:
logFiles.append(h.baseFilename);
else:
logFiles = getAllLoggerFilenames(parent);
return logFiles;
def logBlankLine(logger):
""" This utility method writes a blank line to the log. """
logNames = getAllLoggerFilenames(logger)
for fn in logNames:
with open(fn, 'a') as fh:
fh.write("\n")
Usage:
# We use YAML for logging config files, YMMV:
with open(logConfig, 'rt') as f:
logging.config.dictConfig(yaml.safe_load(f.read()))
logger = logging.getLogger("test.test")
logger.info("line 1")
logBlankLine(logger)
logger.info("line 2")
Output:
2019/12/22 16:33:59.152: INFO : test.test : line 1
2019/12/22 16:33:59.152: INFO : test.test : line 2
来源：https://stackoverflow.com/questions/20111758/how-to-insert-newline-in-python-logging