get just the integer from wc in bash

Is there a way to get the integer that wc returns in bash?

Basically I want to write the line numbers and word counts to the screen after the file name.

output: filename linecount wordcount Here is what I have so far:

files=`ls`
for f in $files;
do
        if [ ! -d $f ] #only print out information about files !directories
        then
                # some way of getting the wc integers into shell variables and then printing them
                echo "$f $lines $ words"
        fi
done

You can use the cut command to get just the first word of wc's output (which is the line or word count):

lines=`wc -l $f | cut -f1 -d' '`
words=`wc -w $f | cut -f1 -d' '`

Most simple answer ever:

wc < filename

sten

Just:

wc -l < file_name

will do the job. But this output includes prefixed whitespace as wc right-aligns the number.

James Broadhead

wc $file | awk {'print "$4" "$2" "$1"'}

Adjust as necessary for your layout.

It's also nicer to use positive logic ("is a file") over negative ("not a directory")

[ -f $file ] && wc $file | awk {'print "$4" "$2" "$1"'}

Sometimes wc outputs in different formats in different platforms. For example:

In OS X:

$ echo aa | wc -l

         1

In Centos:

$ echo aa | wc -l

1

So using only cut may not retrieve the number. Instead try tr to delete space characters:

$ echo aa | wc -l | tr -d ' '

rouble

The accepted/popular answers do not work on OSX.

Any of the following should be portable on bsd and linux.

wc -l < "$f" | tr -d ' '

wc -l "$f" | tr -s ' ' | cut -d ' ' -f 2

wc -l "$f" | awk '{print $1}'

If you redirect the filename into wc it omits the filename on output.

Bash:

read lines words characters <<< $(wc < filename)

read lines words characters <<EOF
$(wc < filename)
EOF

Instead of using for to iterate over the output of ls, do this:

for f in *

which will work if there are filenames that include spaces.

If you can't use globbing, you should pipe into a while read loop:

find ... | while read -r f

or use process substitution

while read -r f
do
    something
done < <(find ...)

Walter Tross

If the file is small you can afford calling wc twice, and use something like the following, which avoids piping into an extra process:

lines=$((`wc -l "$f"`))
words=$((`wc -w "$f"`))

The $((...)) is the Arithmetic Expansion of bash. It removes any whitespace from the output of wc in this case.

This solution makes more sense if you need either the linecount or the wordcount.

How about with sed?

wc -l /path/to/file.ext | sed 's/ *\([0-9]* \).*/\1/'

Try this for numeric result:
nlines=$( wc -l < $myfile )

Try this:

wc `ls` | awk '{ LINE += $1; WC += $2 } END { print "lines: " LINE  " words: " WC }'

It creates a line count, and word count (LINE and WC), and increase them with the values extracted from wc (using $1 for the first column's value and $2 for the second) and finally prints the results.

GeorgesMakarios

typeset -i a=$(wc -l fileName.dat  | xargs echo | cut -d' ' -f1)

"Basically I want to write the line numbers and word counts to the screen after the file name."

answer=(`wc $f`)
echo -e"${answer[3]}
lines:  ${answer[0]}
words:  ${answer[1]}
bytes:  ${answer[2]}"

Outputs : myfile.txt lines: 10 words: 20 bytes: 120

files=`ls`
echo "$files" | wc -l | perl -pe "s#^\s+##"

Another way, similar to what @BananaNeil posted:

$ cat myfile.txt | wc -l

来源：https://stackoverflow.com/questions/3746947/get-just-the-integer-from-wc-in-bash

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bash