Importing files from different folder

问题

I have the following folder structure.

application/app/folder/file.py

and I want to import some functions from file.py in another Python file which resides in

application/app2/some_folder/some_file.py

I\'ve tried

from application.app.folder.file import func_name

and some other various attempts but so far I couldn\'t manage to import properly. How can I do this?

回答1:

By default, you can't. When importing a file, Python only searches the current directory, the directory that the entry-point script is running from, and sys.path which includes locations such as the package installation directory (it's actually a little more complex than this, but this covers most cases).

However, you can add to the Python path at runtime:

# some_file.py
import sys
# insert at 1, 0 is the script path (or '' in REPL)
sys.path.insert(1, '/path/to/application/app/folder')

import file

回答2:

Nothing wrong with:

from application.app.folder.file import func_name

Just make sure folder also contains an __init__.py, this allows it to be included as a package. Not sure why the other answers talk about PYTHONPATH.

回答3:

When modules are in parallel locations, as in the question:

application/app2/some_folder/some_file.py
application/app2/another_folder/another_file.py

This shorthand makes one module visible to the other:

import sys
sys.path.append('../')

回答4:

I think an ad-hoc way would be to use the environment variable PYTHONPATH as described in the documentation: Python2, Python3

# Linux & OSX
export PYTHONPATH=$HOME/dirWithScripts/:$PYTHONPATH

# Windows
set PYTHONPATH=C:\path\to\dirWithScripts\;%PYTHONPATH%

回答5:

First import sys

 import sys

Second append the folder path

sys.path.insert(0, '/the/folder/path/name-folder/')

Third Make a blank file called __ init __.py in your subdirectory (this tells Python it is a module)

name-file.py
name-folder
- __ init __.py
- name-module.py

Fourth import the module inside the folder

from name-folder import name-module

回答6:

Your problem is that Python is looking in the Python directory for this file and not finding it. You must specify that you are talking about the directory that you are in and not the Python one.

To do this you change this:

from application.app.folder.file import func_name

to this:

from .application.app.folder.file import func_name

By adding the dot you are saying look in this folder for the application folder instead of looking in the Python directory.

回答7:

The answers here are lacking in clarity, this is tested on Python 3.6

With this folder structure:

main.py
|
---- myfolder/myfile.py

Where myfile.py has the content:

def myfunc():
    print('hello')

The import statement in main.py is:

from myfolder.myfile import myfunc
myfunc()

and this will print hello.

回答8:

From what I know, add an __init__.py file directly in the folder of the functions you want to import will do the job.

回答9:

Worked for me in python3 on linux

import sys  
sys.path.append(pathToFolderContainingScripts)  
from scriptName import functionName #scriptName without .py extension

回答10:

Considering application as the root directory for your python project, create an empty __init__.py file in application, app and folder folders. Then in your some_file.py make changes as follows to get the definition of func_name:

import sys
sys.path.insert(0, r'/from/root/directory/application')

from application.app.folder.file import func_name ## You can also use '*' wildcard to import all the functions in file.py file.
func_name()

回答11:

I was faced with the same challenge, especially when importing multiple files, this is how I managed to overcome it.

import os, sys

from os.path import dirname, join, abspath
sys.path.insert(0, abspath(join(dirname(__file__), '..')))

from root_folder import file_name

回答12:

In Python 3.4 and later, you can import from a source file directly (link to documentation). This is not the simplest solution, but I'm including this answer for completeness.

Here is an example. First, the file to be imported, named foo.py:

def announce():
    print("Imported!")

The code that imports the file above, inspired heavily by the example in the documentation:

import importlib.util

def module_from_file(module_name, file_path):
    spec = importlib.util.spec_from_file_location(module_name, file_path)
    module = importlib.util.module_from_spec(spec)
    spec.loader.exec_module(module)
    return module

foo = module_from_file("foo", "/path/to/foo.py")

if __name__ == "__main__":
    print(foo)
    print(dir(foo))
    foo.announce()

The output:

<module 'foo' from '/path/to/foo.py'>
['__builtins__', '__cached__', '__doc__', '__file__', '__loader__', '__name__', '__package__', '__spec__', 'announce']
Imported!

Note that the variable name, the module name, and the filename need not match. This code still works:

import importlib.util

def module_from_file(module_name, file_path):
    spec = importlib.util.spec_from_file_location(module_name, file_path)
    module = importlib.util.module_from_spec(spec)
    spec.loader.exec_module(module)
    return module

baz = module_from_file("bar", "/path/to/foo.py")

if __name__ == "__main__":
    print(baz)
    print(dir(baz))
    baz.announce()

The output:

<module 'bar' from '/path/to/foo.py'>
['__builtins__', '__cached__', '__doc__', '__file__', '__loader__', '__name__', '__package__', '__spec__', 'announce']
Imported!

Programmatically importing modules was introduced in Python 3.1 and gives you more control over how modules are imported. Refer to the documentation for more information.

回答13:

Try Python's relative imports:

from ...app.folder.file import func_name

Every leading dot is another higher level in the hierarchy beginning with the current directory.

Problems? If this isn't working for you then you probably are getting bit by the many gotcha's relative imports has. Read answers and comments for more details: How to fix "Attempted relative import in non-package" even with __init__.py

Hint: have __init__.py at every directory level. You might need python -m application.app2.some_folder.some_file (leaving off .py) which you run from the top level directory or have that top level directory in your PYTHONPATH. Phew!

回答14:

This works for me on windows

# some_file.py on mainApp/app2 
import sys
sys.path.insert(0, sys.path[0]+'\\app2')

import some_file

回答15:

Using sys.path.append with an absolute path is not ideal when moving the application to other environments. Using a relative path won't always work because the current working directory depends on how the script was invoked.

Since the application folder structure is fixed, we can use os.path to get the full path of the module we wish to import. For example, if this is the structure:

/home/me/application/app2/some_folder/vanilla.py
/home/me/application/app2/another_folder/mango.py

And let's say that you want to import the "mango" module. You could do the following in vanilla.py:

import sys, os.path
mango_dir = (os.path.abspath(os.path.join(os.path.dirname(__file__), '..'))
+ '/another_folder/')
sys.path.append(mango_dir)
import mango

Of course, you don't need the mango_dir variable.

To understand how this works look at this interactive session example:

>>> import os
>>> mydir = '/home/me/application/app2/some_folder'
>>> newdir = os.path.abspath(os.path.join(mydir, '..'))
>>> newdir
    '/home/me/application/app2'
>>> newdir = os.path.abspath(os.path.join(mydir, '..')) + '/another_folder'
>>> 
>>> newdir
'/home/me/application/app2/another_folder'
>>>

And check the os.path documentation.

回答16:

I'm quite special : I use Python with Windows !

I just complete information : for both Windows and Linux, both relative and absolute path work into sys.path (I need relative paths because I use my scripts on the several PCs and under different main directories).

And when using Windows both \ and / can be used as separator for file names and of course you must double \ into Python strings,
some valid examples :

sys.path.append('c:\\tools\\mydir')
sys.path.append('..\\mytools')
sys.path.append('c:/tools/mydir')
sys.path.append('../mytools')

(note : I think that / is more convenient than \, event if it is less 'Windows-native' because it is Linux-compatible and simpler to write and copy to Windows explorer)

回答17:

If the purpose of loading a module from a specific path is to assist you during the development of a custom module, you can create a symbolic link in the same folder of the test script that points to the root of the custom module. This module reference will take precedence over any other modules installed of the same name for any script run in that folder.

I tested this on Linux but it should work in any modern OS that supports symbolic links.

One advantage to this approach is that you can you can point to a module that's sitting in your own local SVC branch working copy which can greatly simplify the development cycle time and reduce failure modes of managing different versions of the module.

回答18:

I was working on project a that I wanted users to install via pip install a with the following file list:

.
├── setup.py
├── MANIFEST.in
└── a
    ├── __init__.py
    ├── a.py
    └── b
        ├── __init__.py
        └── b.py

setup.py

from setuptools import setup

setup (
  name='a',
  version='0.0.1',
  packages=['a'],
  package_data={
    'a': ['b/*'],
  },
)

MANIFEST.in

recursive-include b *.*

a/init.py

from __future__ import absolute_import

from a.a import cats
import a.b

a/a.py

cats = 0

a/b/init.py

from __future__ import absolute_import

from a.b.b import dogs

a/b/b.py

dogs = 1

I installed the module by running the following from the directory with MANIFEST.in:

python setup.py install

Then, from a totally different location on my filesystem /moustache/armwrestle I was able to run:

import a
dir(a)

Which confirmed that a.cats indeed equalled 0 and a.b.dogs indeed equalled 1, as intended.

回答19:

In my case I had a class to import. My file looked like this:

# /opt/path/to/code/log_helper.py
class LogHelper:
    # stuff here

In my main file I included the code via:

import sys
sys.path.append("/opt/path/to/code/")
from log_helper import LogHelper

回答20:

You can refresh the Python shell by pressing f5, or go to Run-> Run Module. This way you don't have to change the directory to read something from the file. Python will automatically change the directory. But if you want to work with different files from different directory in the Python Shell, then you can change the directory in sys, as Cameron said earlier.

回答21:

So I had just right clicked on my IDE, and added a new folder and was wondering why I wasn't able to import from it. Later I realized I have to right click and create a Python Package, and not a classic file system folder. Or a post-mortem method being adding an __init__.py (which makes python treat the file system folder as a package) as mentioned in other answers. Adding this answer here just in case someone went this route.

回答22:

You can use importlib to import modules where you want to import a module from a folder using a string like so:

import importlib

scriptName = 'Snake'

script = importlib.import_module('Scripts\\.%s' % scriptName)

This example has a main.py which is the above code then a folder called Scripts and then you can call whatever you need from this folder by changing the scriptName variable. You can then use script to reference to this module. such as if I have a function called Hello() in the Snake module you can run this function by doing so:

script.Hello()

I have tested this in Python 3.6

来源：https://stackoverflow.com/questions/4383571/importing-files-from-different-folder

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