问题
My question is simple, I have a dataframe and I groupby
the results based on a column and get the size like this:
df.groupby('column').size()
Now the problem is that I only want the ones where size is greater than X. I am wondering if I can do it using a lambda function or anything similar? I have already tried this:
df.groupby('column').size() > X
and it prints out some True and False values.
回答1:
The grouped result is a regular DataFrame, so just filter the results as usual:
import pandas as pd
df = pd.DataFrame({'a': ['a', 'b', 'a', 'a', 'b', 'c', 'd']})
after = df.groupby('a').size()
>> after
a
a 3
b 2
c 1
d 1
dtype: int64
>> after[after > 2]
a
a 3
dtype: int64
回答2:
Try this code:
df.groupby('column').filter(lambda group: group.size > X)
来源:https://stackoverflow.com/questions/31303417/python-pandas-dataframe-group-by-based-on-a-condition