问题
I'm pretty new to Django and come from the PHP world. I'm trying to 'add' a field to a queryset after computing things, and don't know how to do it. In PHP I would just add a column in an array and store my stuff in it.
Here's my code:
def (id):
mystuff_details = mystuff_details.objects.filter(stuff_id=id)
newthing = '';
for mystuff in mystuff_details:
newthing_lists = //some query to get another queryset
for newthing_list in newthing_lists:
newthing = newthing_list.stuffIwant
//Here I want to make some computation, and ADD something to newthing, let's say:
to_add = (mystuff.score+somethingelse)
//I've heard about the .append but I'm sure I'm screwing it up
newthing.append(to_add)
So basically in my template I'd like to be able to call: {% for newthing in newthings_list %} {{ newthing.to_add }} {% end %}
TL;DR: I basically want to retrieve a list of stuff from my database, and in this list of objects ADD a field that will contain a computed value.
Let me know if it's unclear, I'm having a hard time switching from php to django haha.
Thanks!
EDIT:
So, I'm trying with a dictionnary, but I must be missing the logic:
def (id):
mystuff_details = mystuff_details.objects.filter(stuff_id=id)
newthing = {};
for mystuff in mystuff_details:
newthing_lists = //some query to get another queryset
for newthing_list in newthing_lists:
//Newthing_list can have several times the same I, and the scores need to add up
if newthing[newthing_list.id] > 0: //This doesn't seem to work and throws an error (KeyError)
newthing[newthing_list.id] = newthing[newthing_list.id] + some_calculated_thing
else:
newthing[newthing_list.id] = some_calculated_thing
And then when I'll get that working, I don't know how to access it in the template:
{% for id in my_list %}
{{newthing[id]}} ? Or something like newthing.id ?
{% end %}
Thanks!
回答1:
Why not use a dictionary?
newthing = {}
newthing['your_key'] = to_add
In the template, you can access dictionary values with:
{{newthing.your_key}}
Or use the for loop if you have a dictionary of dictionaries
回答2:
You can set anything on a python object:
for obj in self.model.objects.all() :
obj.score = total_score / total_posts
This will work even if obj does not have a score attribute. In the template request it like so:
{{ obj.score }}
Yes, it's that simple. However, if the calculations you're doing can be done in the database, you should look into annotate.
来源:https://stackoverflow.com/questions/12118776/django-add-field-to-queryset-to-store-computation-results