How i call async function without await?

问题

I have a controller action in aiohttp application.

async def handler_message(request):

    try:
        content = await request.json()
        perform_message(x,y,z)
    except (RuntimeError):
        print("error in perform fb message")
    finally:
        return web.Response(text="Done")

perform_message is async function. Now, when I call action I want that my action return as soon as possible and perform_message put in event loop.

In this way, perform_message isn't executed

回答1:

One way would be to use create_task function:

import asyncio

async def handler_message(request):
    ...
    loop = asyncio.get_event_loop()
    loop.create_task(perform_message(x,y,z))
    ...

回答2:

Other way would be to use ensure_future function:

import asyncio

async def handler_message(request):
...
loop = asyncio.get_event_loop()
loop.ensure_future(perform_message(x,y,z))
...

来源：https://stackoverflow.com/questions/44630676/how-i-call-async-function-without-await