displaying multiple lines of a file, never repeating

守給你的承諾、 提交于 2019-11-27 16:18:18
Gordon

This should work:

$blocks = array_chunk(file('path/to/file'), 10);
foreach($blocks as $number => $block) {
    printf('<div id="%d">%s</div>', 
            $number+1, 
            implode('<br/>', $block));
}

References:

echo '<div class="return-ed" id="1">';
$lineNum = 0;
foreach ($lines as $line) {
    if ($lineNum && !($lineNum % 10)) {
        echo '</div><div class="return-ed" id="'.($lineNum/10+1).'">';
    }
    echo $line."<br />";
    $lineNum++;
}
echo "</div>";

With a quick google search:

http://www.w3schools.com/php/php_file.asp

Reading a File Line by Line

The fgets() function is used to read a single line from a file.

Note: After a call to this function the file pointer has moved to the next line.

Example from W3 Schools:

The example below

reads a file line by line, until the end of file is reached:

<?php
$file = fopen("welcome.txt", "r") or exit("Unable to open file!");
//Output a line of the file until the end is reached
while(!feof($file))
  {
  echo fgets($file). "<br />";
  }
fclose($file);
?>

All you need to do is have your counting variable that counts up to 10 within that while loop. once it hits 10, do what you need to do.

Assuming your lines are in an array that you're echoing, something like this would work:

$count = 0;
$div = 1;
foreach($lines as $line){ //or a for loop, whatever you're using
  if(0 == $count){
    echo "<div id='$div'>";
  }

  $count++;
  echo $line;

  if(10 == $count){
    echo "</div>";
    $count = 0;
  }
}
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