I'm trying to print out my binary tree but Clojure is giving me a hard time printing out the sequences properly.
So, I have a list of nodes '(1 2 3) for example.
In each iteration I want to print out the node with a number of spaces before and after each element.
(defn spaces [n]
(apply str (repeat n " ")))
Great, this seems to work.
So, suppose I have a list of nodes '(:a :b :c) I want to print out on one line, with as said, the spaces.
(println (map #(str (spaces before) % (spaces (dec before))) nodes))
I have a list of items. Using the map I get a list of string objects. Great, so I can print them!
But this gives me this:
(clojure.lang.LazySeq@d0b37c31 clojure.lang.LazySeq@105879a9 clojure.lang.LazySeq@8de18242)
So I googled how to print lazy sequences and I came around to using print-str command. According to the docs this prints to a string which then gets returned.
(println (print-str (map #(str (spaces before) % (spaces (dec before))) nodes)))
But this gives me this:
(clojure.lang.LazySeq@d0b37c31 clojure.lang.LazySeq@105879a9 clojure.lang.LazySeq@8de18242)
No change.. Hrm. Any help is greatly appreciated.
user> (str (map inc (range 10)))
"clojure.lang.LazySeq@c5d38b66"
user> (pr-str (map inc (range 10)))
"(1 2 3 4 5 6 7 8 9 10)"
The toString method of LazySeq is called by str, and this avoids realizing the lazy sequence of values by opaquely showing the Object identity. The pr-str function calls the print-dup multimethod of an object, which is designed to get the version of a thing that could be understood by the reader (so for a LazySeq the literal value that would make an equal LazySeq).
For pretty formatting of structures, do check out the clojure.pprint namespace which comes with clojure.core, which has pprint, print-table, and various functions for customizing the behavior of pretty printing.
user> (require '[clojure.pprint :as pprint :refer [pprint print-table]])
nil
user> (pprint [:a [:b :c :d [:e :f :g] :h :i :j :k] :l :m :n :o :p :q [:r :s :t :u :v] [:w [:x :y :z]]])
[:a
[:b :c :d [:e :f :g] :h :i :j :k]
:l
:m
:n
:o
:p
:q
[:r :s :t :u :v]
[:w [:x :y :z]]]
nil
user> (print-table (map #(let [start (rand-int 1e6)] (zipmap % (range start (+ start 10)))) (repeat 5 [:a :b :c :d :e :f :g :h :i :j])))
| :a | :c | :b | :f | :g | :d | :e | :j | :i | :h |
|--------+--------+--------+--------+--------+--------+--------+--------+--------+--------|
| 311650 | 311652 | 311651 | 311655 | 311656 | 311653 | 311654 | 311659 | 311658 | 311657 |
| 67627 | 67629 | 67628 | 67632 | 67633 | 67630 | 67631 | 67636 | 67635 | 67634 |
| 601726 | 601728 | 601727 | 601731 | 601732 | 601729 | 601730 | 601735 | 601734 | 601733 |
| 384887 | 384889 | 384888 | 384892 | 384893 | 384890 | 384891 | 384896 | 384895 | 384894 |
| 353946 | 353948 | 353947 | 353951 | 353952 | 353949 | 353950 | 353955 | 353954 | 353953 |
nil
来源：https://stackoverflow.com/questions/23405852/clojure-printing-lazy-sequence