问题
I'm using jQuery DataTables to display information from JSON encoded PHP response. The JSON response contains the object "name". "name" contains "Full Name", "Last Name", "ID". I have been using columns
to display the data the way I want but, I've ran into a problem I can't figure out.
In the code below example 1 works fine and will display "Full Name" while sorting by "Last Name". However, example 2 is not working at all. The desired output would contain HTML rendered display and sorted by "Last Name". In example 3 the display is rendered the way I would like but it is not sorted correctly.
Does anyone know how to adjust example 2 to output what I am looking for (rendered and sorted data)?
var oTable = $('#table').DataTable({
'ajax': {
url: 'PHP-file-returns-JSON.php',
type: "POST",
dataSrc: function ( data ) {
return data.cols;
},
data: function(d) {
///send additional values to POST
var frm_data = $('#val1, #val2').serializeArray();
$.each(frm_data, function(key, val) {
d[val.name] = val.value;
});
}
},
'columns':[
// exapmle 1 - works but not rendered with HTML
{ data: {
_: "name.Full Name",
sort: "name.Last Name",
}
},
// example 2 not working at all
{ data: 'name', "render": function ( data, type, row ) {
return '<span id="'+data.ID+'">'+data.Full Name+'</span>';
},
"sort" : "name.Last Name",
},
// example 3 works fine with HTML rendered display but not sorted
{ data: 'name', "render": function ( data, type, row ) {
return '<span id="'+data.ID+'">'+data.Full Name+'</span>';
}
},
]
});
UPDATE:
HERE is the JSFiddle that shows the data structure I'm working with. The working example only shows the Full Name sorted by the Last Name. I am trying to figure out how to make the display contain a span element with the ID as the id attribute.
回答1:
Turns out that using name.Full Name
will not work. It has to be name.FullName
without the space. Here is what ended up working for me.
'columns': [
{
"data": "name",
"render": function ( data, type, row ) {
if(type === 'display'){
return '<span id="'+data.ID+'">'+data.FullName+'</span>';
}else if(type === 'sort'){
return data.LastName;
}else{
return data;
}
}
}
]
回答2:
If you need to sort the column on the last name this should work:
$.extend($.fn.dataTableExt.oSort, {
"last-name-pre": function(a) {
return $(a).data("lastname");
},
"last-name-asc": function(a, b) {
return ((a < b) ? -1 : ((a > b) ? 1 : 0));
},
"last-name-desc": function(a, b) {
return ((a < b) ? 1 : ((a > b) ? -1 : 0));
}
});
$("#example").DataTable({
"data": data,
"columns": [{
"title": "Full Name",
"data": "Full Name",
"render": function(data, type, row) {
return $("<span></span>", {
"text": data,
"data-lastname": row["Last Name"]
}).prop("outerHTML");
},
"type": 'last-name'
}]
});
It's working here. You could also remove the render function and just adapt the last-name
function to split the full name and return the last name:
$.extend($.fn.dataTableExt.oSort, {
"last-name-pre": function(a) {
return a.split(" ")[1];
},
"last-name-asc": function(a, b) {
return ((a < b) ? -1 : ((a > b) ? 1 : 0));
},
"last-name-desc": function(a, b) {
return ((a < b) ? 1 : ((a > b) ? -1 : 0));
}
});
$("#example").DataTable({
"data": data,
"columns": [{
"title": "Full Name",
"data": "Full Name",
"type": 'last-name'
}]
});
Which is here. Hope that helps, and that I've understood your requirements properly.
来源:https://stackoverflow.com/questions/41982049/jquery-datatables-render-column-data