101. 对称二叉树 golang

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func isSymmetric(root *TreeNode) bool {
    if root == nil {
        return true
    }
    return isSymmetric1(root.Left, root.Right)
}

func isSymmetric1(TN1 *TreeNode, TN2 *TreeNode) bool {
    if TN1 == nil && TN2 == nil {
        return true
    }
    if TN1 == nil || TN2 == nil {
        return false
    }

    if TN1.Val != TN2.Val {
        return false
    }

    return isSymmetric1(TN1.Left,TN2.Right) && isSymmetric1(TN1.Right, TN2.Left)
}

来源：CSDN

作者：寇浩哲

链接：https://blog.csdn.net/csdn_kou/article/details/104123579