Detect single string fraction (ex: ½ ) and change it to longer string?

喜你入骨 提交于 2020-01-30 07:33:26

问题


ex: "32 ½ is not very hot " to x = "info: 32, numerator = 1, denominator = 2"

Note: it could be 3/9, but it cannot be simplified into 1/3 aka literally get what is in the string.

I need to detect the fractional string in a longer string and expand the information to a more usable form.

½ has been given to me decoded and is a string with length one.


回答1:


There seem to be 19 such forms (here) and they all start with the name VULGAR FRACTION.

import unicodedata

def fraction_finder(s):
    for c in s:
        try:
            name = unicodedata.name(c)
        except ValueError:
            continue
        if name.startswith('VULGAR FRACTION'):
            normalized = unicodedata.normalize('NFKC', c)
            numerator, _slash, denominator = normalized.partition('⁄')
            yield c, int(numerator), int(denominator)

Demo:

>>> s = "32 ½ is not very hot "
>>> print(*fraction_finder(s))
('½', 1, 2)


来源:https://stackoverflow.com/questions/49440525/detect-single-string-fraction-ex-%c2%bd-and-change-it-to-longer-string

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