How to get a list of points from a UIBezierPath?

僤鯓⒐⒋嵵緔 提交于 2019-11-26 03:38:48

问题


I have a UIBezierPath that I need to take a list of points from.

In Qt there is a function called pointAtPercent that would fit my needs but I can\'t find anything equivalent in Objective-C.

Does anyone know how to do this?


回答1:


You might try this:

UIBezierPath *yourPath; // Assume this has some points in it
CGPath yourCGPath = yourPath.CGPath;
NSMutableArray *bezierPoints = [NSMutableArray array];
CGPathApply(yourCGPath, bezierPoints, MyCGPathApplierFunc);

The path applier function will be handed each of the path's path elements in turn.
Check out CGPathApplierFunction and CGPathApply.

The path applier function might look something like this

void MyCGPathApplierFunc (void *info, const CGPathElement *element) {
    NSMutableArray *bezierPoints = (NSMutableArray *)info;

    CGPoint *points = element->points;
    CGPathElementType type = element->type;

    switch(type) {
        case kCGPathElementMoveToPoint: // contains 1 point
            [bezierPoints addObject:[NSValue valueWithCGPoint:points[0]]];
            break;

        case kCGPathElementAddLineToPoint: // contains 1 point
            [bezierPoints addObject:[NSValue valueWithCGPoint:points[0]]];            
            break;

        case kCGPathElementAddQuadCurveToPoint: // contains 2 points
            [bezierPoints addObject:[NSValue valueWithCGPoint:points[0]]];
            [bezierPoints addObject:[NSValue valueWithCGPoint:points[1]]];            
            break;

        case kCGPathElementAddCurveToPoint: // contains 3 points
            [bezierPoints addObject:[NSValue valueWithCGPoint:points[0]]];
            [bezierPoints addObject:[NSValue valueWithCGPoint:points[1]]];
            [bezierPoints addObject:[NSValue valueWithCGPoint:points[2]]];
            break;

        case kCGPathElementCloseSubpath: // contains no point
            break;
    }
}



回答2:


@Moritz Great answer! To find a Swift like solution I strumbled across an approach in this post and implemented a CGPath extension like this to get the points from the path:

extension CGPath {
    func points() -> [CGPoint]
    {
        var bezierPoints = [CGPoint]()
        self.forEach({ (element: CGPathElement) in
            let numberOfPoints: Int = {
                switch element.type {
                case .MoveToPoint, .AddLineToPoint: // contains 1 point
                    return 1
                case .AddQuadCurveToPoint: // contains 2 points
                    return 2
                case .AddCurveToPoint: // contains 3 points
                    return 3
                case .CloseSubpath:
                    return 0
                }
            }()
            for index in 0..<numberOfPoints {
                let point = element.points[index]
                bezierPoints.append(point)
            }
        })
        return bezierPoints
    }

    func forEach(@noescape body: @convention(block) (CGPathElement) -> Void) {
        typealias Body = @convention(block) (CGPathElement) -> Void
        func callback(info: UnsafeMutablePointer<Void>, element: UnsafePointer<CGPathElement>) {
            let body = unsafeBitCast(info, Body.self)
            body(element.memory)
        }
        let unsafeBody = unsafeBitCast(body, UnsafeMutablePointer<Void>.self)
        CGPathApply(self, unsafeBody, callback)
    }
}



回答3:


I think you were trying to do something like this:

https://math.stackexchange.com/questions/26846/is-there-an-explicit-form-for-cubic-bézier-curves

y=u0(1−x^3)+3u1(1−x^2)x+3u2(1−x)x^2+u3x^3

This is my method for printing all values of that function.

- (void)logXY {

    float u0 = 0;
    float u1 = 0.05;
    float u2 = 0.25;
    float u3 = 1;

    for (float x = 0; x <= 10.0; x = x + 0.1) {
        float y = u0 * (1 - x * x * x) + 3 * u1 * (1 - x * x) * x + 3 * u2 * (1 - x) * x * x + u3 * x * x * x;

        NSLog(@"x: %f\ty: %f", x, y);
    }
}

And output is:

x: 0.000000 y: 0.000000
x: 0.100000 y: 0.022600
x: 0.200000 y: 0.060800
x: 0.300000 y: 0.115200
x: 0.400000 y: 0.186400
x: 0.500000 y: 0.275000
x: 0.600000 y: 0.381600
x: 0.700000 y: 0.506800
x: 0.800000 y: 0.651200
x: 0.900000 y: 0.815400
x: 1.000000 y: 1.000000
x: 1.100000 y: 1.205600
x: 1.200000 y: 1.432800
x: 1.300000 y: 1.682200
x: 1.400000 y: 1.954401
x: 1.500000 y: 2.250001
x: 1.600000 y: 2.569601
x: 1.700000 y: 2.913801
x: 1.800000 y: 3.283201
x: 1.900000 y: 3.678401
x: 2.000000 y: 4.100001
x: 2.100000 y: 4.548601
x: 2.200000 y: 5.024800
x: 2.300000 y: 5.529200
x: 2.400000 y: 6.062399
x: 2.500000 y: 6.625000
x: 2.600000 y: 7.217597
x: 2.700000 y: 7.840797
x: 2.799999 y: 8.495197
x: 2.899999 y: 9.181394
x: 2.999999 y: 9.899996



回答4:


I wrote an article about finding the closest point on UIBezierPath, which is very similar to what the OP is looking for. I've also created a demo project on Swift: https://github.com/andrew8712/BezierPathClosestPoint




回答5:


i have modified @FBente post to work with swift 3

extension CGPath {
func points() -> [CGPoint]
{
    var bezierPoints = [CGPoint]()
    self.forEach(body: { (element: CGPathElement) in
        let numberOfPoints: Int = {
            switch element.type {
            case .moveToPoint, .addLineToPoint: // contains 1 point
                return 1
            case .addQuadCurveToPoint: // contains 2 points
                return 2
            case .addCurveToPoint: // contains 3 points
                return 3
            case .closeSubpath:
                return 0
            }
        }()
        for index in 0..<numberOfPoints {
            let point = element.points[index]
            bezierPoints.append(point)
        }
    })
    return bezierPoints
}

func forEach( body: @convention(block) (CGPathElement) -> Void) {
    typealias Body = @convention(block) (CGPathElement) -> Void
    func callback(info: UnsafeMutableRawPointer, element: UnsafePointer<CGPathElement>) {
        let body = unsafeBitCast(info, to: Body.self)
        body(element.pointee)
    }
    let unsafeBody = unsafeBitCast(body, to: UnsafeMutableRawPointer.self)
    self.apply(info: unsafeBody, function: callback as! CGPathApplierFunction)
}
}



回答6:


Updated FBente's extension for Swift 3:

extension CGPath {
  func points() -> [CGPoint]
  {
    var bezierPoints = [CGPoint]()
    self.forEach({ (element: CGPathElement) in
      let numberOfPoints: Int = {
        switch element.type {
        case .moveToPoint, .addLineToPoint: // contains 1 point
          return 1
        case .addQuadCurveToPoint: // contains 2 points
          return 2
        case .addCurveToPoint: // contains 3 points
          return 3
        case .closeSubpath:
          return 0
        }
      }()
      for index in 0..<numberOfPoints {
        let point = element.points[index]
        bezierPoints.append(point)
      }
    })
    return bezierPoints
  }

  func forEach(_ body: @convention(block) (CGPathElement) -> Void) {
    typealias Body = @convention(block) (CGPathElement) -> Void
    func callback(info: UnsafeMutableRawPointer, element: UnsafePointer<CGPathElement>) {
      let body = unsafeBitCast(info, to: Body.self)
      body(element.pointee)
    }
    let unsafeBody = unsafeBitCast(body, to: UnsafeMutableRawPointer.self)
    self.apply(info: unsafeBody, function: callback as! CGPathApplierFunction)
  }
}



回答7:


swift 4.0:

    var bezierPoints = NSMutableArray()
    yourPath.apply(info: &bezierPoints, function: { info, element in

        guard let resultingPoints = info?.assumingMemoryBound(to: NSMutableArray.self) else {
            return
        }

        let points = element.pointee.points
        let type = element.pointee.type

        switch type {
        case .moveToPoint:
            resultingPoints.pointee.add([NSNumber(value: Float(points[0].x)), NSNumber(value: Float(points[0].y))])

        case .addLineToPoint:
            resultingPoints.pointee.add([NSNumber(value: Float(points[0].x)), NSNumber(value: Float(points[0].y))])

        case .addQuadCurveToPoint:
            resultingPoints.pointee.add([NSNumber(value: Float(points[0].x)), NSNumber(value: Float(points[0].y))])
            resultingPoints.pointee.add([NSNumber(value: Float(points[1].x)), NSNumber(value: Float(points[1].y))])

        case .addCurveToPoint:
            resultingPoints.pointee.add([NSNumber(value: Float(points[0].x)), NSNumber(value: Float(points[0].y))])
            resultingPoints.pointee.add([NSNumber(value: Float(points[1].x)), NSNumber(value: Float(points[1].y))])
            resultingPoints.pointee.add([NSNumber(value: Float(points[2].x)), NSNumber(value: Float(points[2].y))])

        case .closeSubpath:
            break
        }
    })


来源:https://stackoverflow.com/questions/3051760/how-to-get-a-list-of-points-from-a-uibezierpath

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