How to get yesterday and day before yesterday in linux?

问题

I want to get sysdate -1 and sysdate -2 in variable and echo it. I am using below query which gives todays date as output.

#! /bin/bash
tm=$(date +%Y%d%m)
echo $tm

How to get yesterday and day before yesterdays date?

回答1:

Here is another one way,

For yesterday,

date -d '-1 day' '+%Y%d%m'

For day before yesterday,

date -d '-2 day' '+%Y%d%m'

回答2:

1. Yesterday date

   YES_DAT=$(date --date=' 1 days ago' '+%Y%d%m')
   

2. Day before yesterdays date

   DAY_YES_DAT=$(date --date=' 2 days ago' '+%Y%d%m')
   

For any date you can use below one default it take 1 days. If its passing value that day before it take

ANY_YES_DAT=$(date --date=' $1 days ago' '+%Y%d%m')

回答3:

You can get the yesterday date by this:

date -d "yesterday 13:00 " '+%Y-%m-%d'

and day before yesterday by this:-

date -d "yesterday-1 13:00 " '+%Y-%m-%d'

回答4:

For older versions of BSD date (on old versions of macOS for example) which don't provide a -v option, you can get yesterdays date by subtracting 86400 seconds (seconds in a day) from the current epoch.

date -r $(( $(date '+%s') - 86400 ))

Obviously, you can subtract 2 * 86400 away for the day for yesterday etc.

Edit: Add reference to old macOS versions.

来源：https://stackoverflow.com/questions/22043088/how-to-get-yesterday-and-day-before-yesterday-in-linux