问题
This is so broken, I hope you are merciful with me:
reactor.callLater(0, myFunction, parameter1).addCallback(reactor.stop)
reactor.run()
myFunction
returns a deferred.
I hope it is clear what I want to do:
- as soon as the reactor is running, I want to call
myFunction
. That is why I am using 0 as the delay parameter. Is there no other way except callLater? It looks funny to pass it a delay of 0. - I want to stop the reactor as soon as
myFunction
has completed the task.
The problems that I have so far:
AttributeError: DelayedCall instance has no attribute 'addCallback'
. Fair enough! How do I put a callback in the callback chain started bymyFunction
then?exceptions.TypeError: stop() takes exactly 1 argument (2 given)
.
To solve the second problem I had to define a special function:
def stopReactor(result):
gd.log.info( 'Result: %s' % result)
gd.log.info( 'Stopping reactor immediatelly' )
reactor.stop()
And change the code to:
reactor.callLater(0, myFunction, parameter1).addCallback(stopReactor)
reactor.run()
(still not working because of the callLater problem, but stopReactor
will work now)
Is there really no other way to call reactor.stop
except by defining an extra function?
回答1:
IReactorTime.callLater
and Deferred
are mixed together by twisted.internet.task.deferLater
.
from twisted.internet import reactor, task
d = task.deferLater(reactor, 0, myFunction, parameter1)
d.addCallback(lambda ignored: reactor.stop())
reactor.run()
回答2:
I want to stop the reactor as soon as myFunction has completed the task.
So, create a wrapper that does myFunction's work and then stops the reactor?
def wrapper(reactor, *args):
myFunction(*args)
reactor.stop()
reactor.callLater(0, wrapper, reactor, ...)
回答3:
You need to attach the callback to the deferred that myFunction returns, since callLater doesn't return a function. Something like this might work:
reactor.callLater(0, lambda: myFunction(parameter1).addCallback(lambda _: reactor.stop())
But this is not tested.
You need to write a new function (here the lambda _: reactor.stop()) because callbacks to a deferred always take the result up to then. If you find yourself wanting to use callbacks for their side-effects and you don't care about propagating values often, you could define a little helper function:
def ignoringarg(f):
return lambda _: f()
And then do:
reactor.callLater(0, lambda: myFunction(paramater1).addCallback(ignoringarg(reactor.stop)))
(What would be really neat would be to define an __rshift__
(and in-place analogue) for the Deferred
class so you could do: myFunction(parameter1) >> reactor.stop
, for when you want to abandon the argument, or myFunction(parameter1) >>= someotherfunc
for when you want to propagate the argument. If you think that abusing haskellish syntax is "neat", anyway.)
回答4:
If You need to trigger callback with some action, just do it (possibly there's no need to return deferred, or smth). Just to clarify things (using purely deferreds):
from twisted.internet import reactor, defer
# That will be our deferred to play with
# it has callback and errback methods
d = defer.Deferred()
def my_function(x):
print 'function', x
# need to trigger deferred upon function run?
# Lets tell it to do so:
d.callback(x)
# That's our callback to run after triggering `d`
def d_callback(y):
print 'callback ', y
# now let's bind that callback to be actually launched by `d`
d.addCallback(d_callback)
# now adding another callback just to stop reactor
# note lambda simply helps to agree number of arguments
d.addCallback(lambda data: reactor.stop())
# so we'll call `my_function` in 2 secs, then it runs
# then it triggers `d` to fire its callbacks
# then `d` actually detonates the whole chain of its added callbacks
reactor.callLater(2, my_function, 'asdf') # 'asdf' is some stupid param
# Here how it works
print 'Lets start!'
reactor.run()
print 'Done!'
来源:https://stackoverflow.com/questions/8174437/how-to-combine-calllater-and-addcallback