How to open .xcodeproj programmatically?

问题

I have projects called A.xcodeproj, B.xcodeproj, C.xcodeproj

now what is question, in AppDelegate of Project A , open project B and C on condition.

int run;

run = 0;

if(run == 0)
{
    Open project B.xcodeproj
}
else
{
    Open project C.xcodeproj
}

Help

Thanks in Advance.

回答1:

on the command line use open to OPEN and SHOW xcode..
so in your case, when run == 0

when you want to BUILD the xcode project, invoke xcodebuild instead of open!..
so in your case, when run == 1

来源：https://stackoverflow.com/questions/24820384/how-to-open-xcodeproj-programmatically