Have decimal amount, want to trim to 2 decimal places if present

问题

Have decimal amount, want to trim to 2 decimal places if present

回答1:

Have you tried using value = Decimal.Round(value, 2)?

For example:

using System;

class Test
{    
    static void Main()
    {
        decimal d = 1234.5678m;
        Console.WriteLine("Before: {0}", d); // Prints 1234.5678
        d = decimal.Round(d, 2);
        Console.WriteLine("After: {0}", d); // Prints 1234.57
    }
}

Note that this is rounding rather than just trimming (so here it's rounded up)... what exactly do you need? Chances that the Decimal struct supports whatever you need to do. Consult MSDN for more options.

回答2:

decimal.Truncate(myDecimal * 100) / 100

This would cut away everything following the first two decimal places. For rounding see Jon's answer.

回答3:

If its just for display purposes, you can use:

Console.Out.WriteLine("Number is: {0:F2}", myDecimalNumber);

回答4:

This should work (EDIT: Fixed to remove rounding):

((Int32)(value * Math.Pow(10, decimalPlaces))) / (Math.Pow(10D, decimalPlaces));

回答5:

I use this: Math.Round(MyDecimalValue,2);

来源：https://stackoverflow.com/questions/4695053/have-decimal-amount-want-to-trim-to-2-decimal-places-if-present