Append an int to char*

问题

How would you append an integer to a char* in c++?

回答1:

First convert the int to a char* using sprintf():

char integer_string[32];
int integer = 1234;

sprintf(integer_string, "%d", integer);

Then to append it to your other char*, use strcat():

char other_string[64] = "Integer: "; // make sure you allocate enough space to append the other string

strcat(other_string, integer_string); // other_string now contains "Integer: 1234"

回答2:

You could also use stringstreams.

char *theString = "Some string";
int theInt = 5;
stringstream ss;
ss << theString << theInt;

The string can then be accessed using ss.str();

回答3:

Something like:

width = floor(log10(num))+1;
result = malloc(strlen(str)+len));
sprintf(result, "%s%*d", str, width, num);

You could simplify len by using the maximum length for an integer on your system.

edit oops - didn't see the "++". Still, it's an alternative.

来源：https://stackoverflow.com/questions/347132/append-an-int-to-char