问题
I have following script which is converting a CSV file to an XLSX file, but my column size is very narrow. Each time I have to drag them with mouse to read data. Does anybody know how to set column width in openpyxl?
Here is the code I am using.
#!/usr/bin/python2.6
import csv
from openpyxl import Workbook
from openpyxl.cell import get_column_letter
f = open('users_info_cvs.txt', "rU")
csv.register_dialect('colons', delimiter=':')
reader = csv.reader(f, dialect='colons')
wb = Workbook()
dest_filename = r"account_info.xlsx"
ws = wb.worksheets[0]
ws.title = "Users Account Information"
for row_index, row in enumerate(reader):
for column_index, cell in enumerate(row):
column_letter = get_column_letter((column_index + 1))
ws.cell('%s%s'%(column_letter, (row_index + 1))).value = cell
wb.save(filename = dest_filename)
回答1:
You could estimate (or use a mono width font) to achieve this. Let's assume data is a nested array like [['a1','a2'],['b1','b2']]
We can get the max characters in each column. Then set the width to that. Width is exactly the width of a monospace font (if not changing other styles at least). Even if you use a variable width font it is a decent estimation. This will not work with formulas.
column_widths = []
for row in data:
for i, cell in enumerate(row):
if len(column_widths) > i:
if len(cell) > column_widths[i]:
column_widths[i] = len(cell)
else:
column_widths += [len(cell)]
for i, column_width in enumerate(column_widths):
worksheet.column_dimensions[get_column_letter(i+1)].width = column_width
A bit of a hack but your reports will be more readable.
回答2:
My variation of Bufke's answer. Avoids a bit of branching with the array and ignores empty cells / columns.
Now fixed for non-string cell values.
ws = your current worksheet
dims = {}
for row in ws.rows:
for cell in row:
if cell.value:
dims[cell.column] = max((dims.get(cell.column, 0), len(str(cell.value))))
for col, value in dims.items():
ws.column_dimensions[col].width = value
回答3:
Even more pythonic way to set the width of all columns that works at least in openpyxl version 2.4.0:
for column_cells in worksheet.columns:
length = max(len(as_text(cell.value)) for cell in column_cells)
worksheet.column_dimensions[column_cells[0].column].width = length
The as_text function should be something that converts the value to a proper length string, like for Python 3:
def as_text(value):
if value is None:
return ""
return str(value)
回答4:
I have a problem with merged_cells and autosize not work correctly, if you have the same problem, you can solve with the next code:
for col in worksheet.columns:
max_length = 0
column = col[0].column # Get the column name
for cell in col:
if cell.coordinate in worksheet.merged_cells: # not check merge_cells
continue
try: # Necessary to avoid error on empty cells
if len(str(cell.value)) > max_length:
max_length = len(cell.value)
except:
pass
adjusted_width = (max_length + 2) * 1.2
worksheet.column_dimensions[column].width = adjusted_width
回答5:
A slight improvement of the above accepted answer, that I think is more pythonic (asking for forgiveness is better than asking for permission)
column_widths = []
for row in workSheet.iter_rows():
for i, cell in enumerate(row):
try:
column_widths[i] = max(column_widths[i], len(cell.value))
except IndexError:
column_widths.append(len(cell.value))
for i, column_width in enumerate(column_widths):
workSheet.column_dimensions[get_column_letter(i + 1)].width = column_width
回答6:
This is my version referring @Virako 's code snippet
def adjust_column_width_from_col(ws, min_row, min_col, max_col):
column_widths = []
for i, col in \
enumerate(
ws.iter_cols(min_col=min_col, max_col=max_col, min_row=min_row)
):
for cell in col:
value = cell.value
if value is not None:
if isinstance(value, str) is False:
value = str(value)
try:
column_widths[i] = max(column_widths[i], len(value))
except IndexError:
column_widths.append(len(value))
for i, width in enumerate(column_widths):
col_name = get_column_letter(min_col + i)
value = column_widths[i] + 2
ws.column_dimensions[col_name].width = value
And how to use is as follows,
adjust_column_width_from_col(ws, 1,1, ws.max_column)
回答7:
All the above answers are generating an issue which is that col[0].column is returning number while worksheet.column_dimensions[column] accepts only character such as 'A', 'B', 'C' in place of column. I've modified @Virako's code and it is working fine now.
import re
import openpyxl
..
for col in _ws.columns:
max_lenght = 0
print(col[0])
col_name = re.findall('\w\d', str(col[0]))
col_name = col_name[0]
col_name = re.findall('\w', str(col_name))[0]
print(col_name)
for cell in col:
try:
if len(str(cell.value)) > max_lenght:
max_lenght = len(cell.value)
except:
pass
adjusted_width = (max_lenght+2)
_ws.column_dimensions[col_name].width = adjusted_width
回答8:
We can convert numbers to their ASCII values and give it to column_dimension parameter
import openpyxl as xl
work_book = xl.load_workbook('file_location')
sheet = work_book['Sheet1']
column_number = 2
column = str(chr(64 + column_number))
sheet.column_dimensions[column].width = 20
work_book.save('file_location')
回答9:
I had to change @User3759685 above answer to this when the openpxyl updated. I was getting an error. Well @phihag reported this in the comments as well
for column_cells in ws.columns:
new_column_length = max(len(as_text(cell.value)) for cell in column_cells)
new_column_letter = (openpyxl.utils.get_column_letter(column_cells[0].column))
if new_column_length > 0:
ws.column_dimensions[new_column_letter].width = new_column_length + 1
回答10:
After update from openpyxl2.5.2a to latest 2.6.4 (final version for python 2.x support), I got same issue in configuring the width of a column.
Basically I always calculate the width for a column (dims is a dict maintaining each column width):
dims[cell.column] = max((dims.get(cell.column, 0), len(str(cell.value))))
Afterwards I am modifying the scale to something shortly bigger than original size, but now you have to give the "Letter" value of a column and not anymore a int value (col below is the value and is translated to the right letter):
worksheet.column_dimensions[get_column_letter(col)].width = value +1
This will fix the visible error and assigning the right width to your column ;) Hope this help.
回答11:
Here is an answer for Python 3.8 and OpenPyXL 3.0.0.
I tried to avoid using the get_column_letter function but failed.
This solution uses the newly introduced assignment expressions aka "walrus operator":
import openpyxl
from openpyxl.utils import get_column_letter
workbook = openpyxl.load_workbook("myxlfile.xlsx")
worksheet = workbook["Sheet1"]
MIN_WIDTH = 10
for i, column_cells in enumerate(worksheet.columns, start=1):
width = (
length
if (length := max(len(str(cell_value) if (cell_value := cell.value) is not None else "")
for cell in column_cells)) >= MIN_WIDTH
else MIN_WIDTH
)
worksheet.column_dimensions[get_column_letter(i)].width = width
来源：https://stackoverflow.com/questions/13197574/openpyxl-adjust-column-width-size