Unreported exception javax.script.ScriptException; must be caught or declared to be thrown

问题

This is a calculator App. When I try and compile it comes up with the following message unreported exception javax.script.ScriptException; must be caught or declared to be thrown

I have a feeling it is because the class is set as ActionEvent. I am a student so I am still learning :)

Any ideas? Thanks

回答1:

You can do the following:

// .. other imports
import javax.script.ScriptException;

// .. the rest of your code
if(source==buteq){
  try{
     ScriptEngineManager manager = new ScriptEngineManager();
     ScriptEngine se = manager.getEngineByName("JavaScript");        
     Object result = se.eval(createEquasion);
     finalAnswer = result.toString();
     answer.setText(finalAnswer);
  catch(ScriptEngineManager e) {
     // handle exception
     System.err.println("Error evaluating the script: " + e.getMessage());
  }
}

In case you are dealing with any kind of exception outside of the method you can add a throws declaration on your methods signature:

// .. other imports
import javax.script.ScriptException;

// your method signature
public void actionPerformed (ActionEvent e) throws ScriptException {

// ...

ScriptEngineManager manager = new ScriptEngineManager();
ScriptEngine se = manager.getEngineByName("JavaScript");        
Object result = se.eval(createEquasion);
finalAnswer = result.toString();
answer.setText(finalAnswer);

// ...

This should be it.

回答2:

In your this actionPerformed method the line se.eval(createEquasion); is throwing ScriptException. you have to handle this Excpetion.

Add below code to complie the class

Object result = null;
            try {
                result = se.eval(createEquasion);
            } catch (ScriptException e1) {
                // TODO Auto-generated catch block
                e1.printStackTrace();
            }
            if (result != null)
                finalAnswer = result.toString();

回答3:

ScriptEngine.html#eval can throws two Exception

NullPointerException
ScriptException

NullPointerException is RuntimeException so compiler will not force you to handle this.But ScriptException is checked Exception, so compiler will force you to handle this Exception either insert the code block into try catch or throw it.

try-catch block

if(source==buteq){
       try{
            ScriptEngineManager manager = new ScriptEngineManager();
            ScriptEngine se = manager.getEngineByName("JavaScript");        
            Object result = se.eval(createEquasion);
            finalAnswer = result.toString();
            answer.setText(finalAnswer);
       }catch(ScriptException se){
            ...
       }
}

ScriptException class declaration -

public class ScriptException extends Exception{...}

Please find more information -

Checked Exception ScriptException
ScriptEngine.html#eval(java.lang.String)

来源：https://stackoverflow.com/questions/15195253/unreported-exception-javax-script-scriptexception-must-be-caught-or-declared-to

标签

java

events

action