Func<T>() vs Func<T>.Invoke()

问题

I'm curious about the differences between calling a Func directly vs using Invoke() on it. Is there a difference ? Is the first, syntactical sugar, and calls Invoke() underneath anyway ?

public T DoWork<T>(Func<T> method)
{
    return (T)method.Invoke();
}

vs

public T DoWork<T>(Func<T> method)
{
    return (T)method();
}

Or am I on the wrong track entirely :) Thanks.

回答1:

There's no difference at all. The second is just a shorthand for Invoke, provided by the compiler. They compile to the same IL.

回答2:

Invoke works well with new C# 6 null propagation operator, now you can do

T result = method?.Invoke();

instead of

T result = method != null ? method() : null;

来源：https://stackoverflow.com/questions/16309286/funct-vs-funct-invoke