What is the difference node *node1 vs node* node1? [duplicate]

问题

This question already has answers here:

Placement of the asterisk in pointer declarations (13 answers)

Closed 2 years ago.

I have 1 node:

struct node
    {
        int key;
        struct node *left, *right;
    };

What is the difference between

node  *node1

vs

node*  node1

?

回答1:

Without a typedef, both the declarations are illegal.

With a typedef like

 typedef struct node node;

in place, there's no difference. Both the statements declare a variable node1 of type pointer to node. (Note: You'll still be needing the terminating ;, though).

It's a matter of choice, but some (including me) prefer to attach the pointer notation to the variable, to avoid misunderstanding, in case of multiple variable declaration, like

 node *p, q;

where, p is pointer type, but q is not.

Writing it like

 node* p, q;

may create the illusion that p and q both are of pointer type, where, in essence, they are not.

来源：https://stackoverflow.com/questions/44055033/what-is-the-difference-node-node1-vs-node-node1