问题
I'm trying to write a script that does something a bit more sophisticated than what I'm going to show you, but I know that the problem is in this part.
I want each name of a list of files in a directory to be assigned to a variable (the same variable, one at a time) through a for loop, then do something inside of the loop with this, see what mean:
for thing in $(ls $1);
do
file $thing;
done
Edit: let's say this scrypt is called Scrypt and I have a folder named Folder, and it has 3 files inside named A,B,C. I want it to show me on the terminal when I write this:
./scrypt Folder
the following:
A: file
B: file
C: file
With the code I've shown above, I get this:
A: ERROR: cannot open `A' (No such file or directory)
B: ERROR: cannot open `B' (No such file or directory)
C: ERROR: cannot open `C' (No such file or directory)
that is the problem
回答1:
One way is to use wildcard expansion instead of ls, e.g.,
for filename in "$1"/*; do
command "$filename"
done
This assumes that $1 is the path to a directory with files in it.
If you want to only operate on plain files, add a check right after do along the lines of:
[ ! -f "$filename" ] && continue
回答2:
http://mywiki.wooledge.org/ParsingLs
Use globbing instead:
for filename in "$1"/* ; do
<cmd> "$filename"
done
Note the quotes around $filename
回答3:
It's a bit unclear what you are trying to accomplish, but you can essentially do the same thing with functionality that already exists with find. For example, the following prints the contents of each file found in a folder:
find FolderName -type f -maxdepth 1 -exec cat {} \;
回答4:
well, i think that what you meant is that the loop will show the filenames in the desired dir. so, i would do it like that:
for filename in "$1"/*; do
echo "file: $filename"
done
that way the result should be (in case in the dir are 3 files and the names are A B C:
`file: A
`file: B
`file: C
来源：https://stackoverflow.com/questions/13519442/assign-file-names-to-a-variable-in-shell