Intercept console.log but keep stack

问题

I know its easy to intercept a function in js, among other ways:

console.log = (function () {
var log = console.log;

return function () {
    alert(arguments);
    log.apply(console, arguments);
})();

but Is there a way to wrap console.log such that when a user calls

console.log("hi")//in random.js

in the console it shows the random.js origin, and not the location of the intercept?

回答1:

Use a try/catch rather than returning a function:

console.log = Function("a", "try { console.info(a); } catch(e){return e}");

来源：https://stackoverflow.com/questions/25540308/intercept-console-log-but-keep-stack