问题
I want to place a gradient over an <img>
tag. src
attribute of the tag is angular-item. For example:
<img src={{value.angitem.image}}>
I've tried to make css class:
.pickgradient {
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(0,0,0,0)), color-stop(100%,rgba(0,0,0,0.65)));
}
and
<img src={{value.angitem.image}} class="pickgradient ">
but it doesn't work. What should I do?
回答1:
With z-index :
You may use a container and put the gradient on that container. Then use a negative z-index to position image behind the gradient.
.pickgradient {
display:inline-block;
background: -moz-linear-gradient(top, rgba(0,0,0,0) 0%, rgba(0,0,0,0.65) 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(0,0,0,0.65)), color-stop(100%,rgba(0,0,0,0))); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, rgba(0,0,0,0) 0%,rgba(0,0,0,0.65) 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, rgba(0,0,0,0) 0%,rgba(0,0,0,0.65) 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, rgba(0,0,0,0) 0%,rgba(0,0,0,0.65) 100%); /* IE10+ */
background: linear-gradient(to bottom, rgba(0,0,0,0) 0%,rgba(0,0,0,0.65) 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#a6000000', endColorstr='#00000000',GradientType=0 ); /* IE6-9 */
}
img{
position:relative;
z-index:-1;
display:block;
height:200px; width:auto;
}
<div class="pickgradient">
<img src="http://i.imgur.com/HDssntn.jpg" />
</div>
With a pseudo element :
As commented, you can also use a pseudo element with the gradient and absolute positioning to put the gradient over the image :
.pickgradient{
position:relative;
display:inline-block;
}
.pickgradient:after {
content:'';
position:absolute;
left:0; top:0;
width:100%; height:100%;
display:inline-block;
background: -moz-linear-gradient(top, rgba(0,0,0,0) 0%, rgba(0,0,0,0.65) 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(0,0,0,0.65)), color-stop(100%,rgba(0,0,0,0))); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, rgba(0,0,0,0) 0%,rgba(0,0,0,0.65) 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, rgba(0,0,0,0) 0%,rgba(0,0,0,0.65) 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, rgba(0,0,0,0) 0%,rgba(0,0,0,0.65) 100%); /* IE10+ */
background: linear-gradient(to bottom, rgba(0,0,0,0) 0%,rgba(0,0,0,0.65) 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#a6000000', endColorstr='#00000000',GradientType=0 ); /* IE6-9 */
}
img{
display:block;
height:200px;width:auto;
}
<div class="pickgradient">
<img src="http://i.imgur.com/HDssntn.jpg" />
</div>
回答2:
try placing a div
over the image in question and placing the gradient on the div instead of the image.
来源:https://stackoverflow.com/questions/23935758/gradient-over-img-tag-using-css