问题
Is there a shorthand for a new line character in Scala? In Java (on Windows) I usually just use "\n", but that doesn't seem to work in Scala - specifically
val s = """abcd
efg"""
val s2 = s.replace("\n", "")
println(s2)
outputs
abcd
efg
in Eclipse,
efgd
(sic) from the command line, and
abcdefg
from the REPL (GREAT SUCCESS!)
String.format("%n") works, but is there anything shorter?
回答1:
Your Eclipse making the newline marker the standard Windows \r\n, so you've got "abcd\r\nefg". The regex is turning it into "abcd\refg" and Eclipse console is treaing the \r slightly differently from how the windows shell does. The REPL is just using \n as the new line marker so it works as expected.
Solution 1: change Eclipse to just use \n newlines.
Solution 2: don't use triple quoted strings when you need to control newlines, use single quotes and explicit \n characters.
Solution 3: use a more sophisticated regex to replace \r\n, \n, or \r
回答2:
A platform-specific line separator is returned by
sys.props("line.separator")
This will give you either "\n" or "\r\n", depending on your platform. You can wrap that in a val as terse as you please, but of course you can't embed it in a string literal.
If you're reading text that's not following the rules for your platform, this obviously won't help.
References:
- scala.sys package scaladoc (for sys.props)
- java.lang.System.getProperties javadoc (for "line.separator")
回答3:
If you're sure the file's line separator in the one, used in this OS, you should do the following:
s.replaceAll(System.lineSeparator, "")
Elsewhere your regex should detect the following newline sequences: "\n" (Linux), "\r" (Mac), "\r\n" (Windows):
s.replaceAll("(\r\n)|\r|\n", "")
The second one is shorter and, I think, is more correct.
回答4:
Try this interesting construction :)
import scala.compat.Platform.EOL
println("aaa"+EOL+"bbb")
回答5:
var s = """abcd
efg""".stripMargin.replaceAll("[\n\r]","")
回答6:
Use \r\n instead
Before:
After:
来源：https://stackoverflow.com/questions/6193960/new-line-character-in-scala