How can I check if a point is below a line or not ?

为君一笑 提交于 2020-01-10 01:58:49

问题


How can I check if a point is below a line or not ?

I've the following data:

Line [ {x1,y1}, {x2,y2} ]
Points {xA,yA}, {xB,yB} ...

I need to write a small algorithm in python to detect points on one side and the other side of the line.

thanks


回答1:


You could try using a cross product -- http://en.wikipedia.org/wiki/Cross_product.

v1 = (x2-x1, y2-y1)   # Vector 1
v2 = (x2-xA, y2-yA)   # Vector 1
xp = v1[0]*v2[1] - v1[1]*v2[0]  # Cross product
if xp > 0:
    print 'on one side'
elif xp < 0:
    print 'on the other'
else:
    print 'on the same line!'

You'd need to calibrate what each side is. If you want it to be "below" or "above" you need to ensure the points on the line are sorted horizontally.

I haven't tested this.

Edit I initially put in the dot product formula. :o

Edit 2 D'oh, I was putting the coordinates into a set instead of a tuple. Using namedtuple('point', 'x y') for the vectors is nice if you're running a reasonably modern version of Python.

Luckily I found Calculating a 2D Vector's Cross Product.




回答2:


You could try using a cross product, but the trick is how to choose the point to form a vector, here I choose the closest point from points, assume I got pointA(you can fairly loop points to calculate to distance from loop point to Line):

v1 = {x2-x1, y2-y1}   # Vector 1
v2 = {xA-x1, yA-y1}   # Vector 2
cross_product = v1.x*v2.y - v1.y*v2.x
if cross_product > 0:
    print 'pointA is on the counter-clockwise side of line'
elif xp < 0:
    print 'pointA is on the clockwise side of line'
else:
    print 'pointA is exactly on the line'



回答3:


Lets say you've given 2 points A, B and you want to know in which halfplane a third point C lies. The terms "below" and "above" as criteria are very vague, so you need a reference point, for example the origin. Just be sure this reference point is not collinear with A and B.

What you have now is a triangle (A, B, C). Using the determinant you can calculate the signed area (see here, or here). The only interesting thing here is to remember the sign.

Next step: for a given point D calculate the signed area of the triangle (A, B, D). If the result has the same sign as the area of your reference triangle -> C and D are on the same side of (A, B). If the sign differs -> C and D lie on opposite sides of the line. If the area of (A, B, D) is 0 then A, B and D are collinear. Note: use the Python builtin cmp to compare the triangle areas.



来源:https://stackoverflow.com/questions/3838319/how-can-i-check-if-a-point-is-below-a-line-or-not

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!