问题
If a user types in [[0,0,0], [0,0,1], [1,1,0]] and press enter,
the program should convert this string to several lists;
one list holding [0][0][0], other for [0][0][1], and the last list for [1][1][0]
Does python have a good way to handle this?
回答1:
This is a little more flexible than Satoru's, and doesn't use any libraries. Still, it won't work with more deeply nested lists. For that, I think you would need a recursive function (or loop), or eval.
str = "[[0,0,0],[0,0,1],[1,1,0]]"
strs = str.replace('[','').split('],')
lists = [map(int, s.replace(']','').split(',')) for s in strs]
lists now contains the list of lists you want.
回答2:
>>> import ast
>>> ast.literal_eval('[[0,0,0], [0,0,1], [1,1,0]]')
[[0, 0, 0], [0, 0, 1], [1, 1, 0]]
For tuples
>>> ast.literal_eval('[(0,0,0), (0,0,1), (1,1,0)]')
[(0, 0, 0), (0, 0, 1), (1, 1, 0)]
回答3:
>>> import json
>>> json.loads('[[0,0,0], [0,0,1], [1,1,0]]')
[[0, 0, 0], [0, 0, 1], [1, 1, 0]]
回答4:
[[int(i) for i in x.strip(" []").split(",")] for x in s.strip('[]').split("],")]
a list comprehension in a list comprehension... but that will melt your brain
回答5:
>>> import re
>>> list_strs = re.findall(r'\[\d+\,\d+\,\d+\]', s)
>>> [[[int(i)] for i in l[1:-1].split(',')] for l in list_str]
回答6:
>>> string='[[0,0,0], [0,0,1], [1,1,0]]'
>>> eval(string)
[[0, 0, 0], [0, 0, 1], [1, 1, 0]]
>>> a=eval(string)
>>> a
[[0, 0, 0], [0, 0, 1], [1, 1, 0]]
before passing your string to eval(), do the necessary sanitization first.
来源：https://stackoverflow.com/questions/2644221/how-can-i-convert-this-string-to-list-of-lists