How to round decimal value up to nearest 0.05 value?

问题

Is there any way to round up decimal value to its nearest 0.05 value in .Net?

Ex:

7.125 -> 7.15

6.66 -> 6.7

If its now available can anyone provide me the algo?

回答1:

How about:

Math.Ceiling(myValue * 20) / 20

回答2:

Use this:

Math.Round(mydecimal / 0.05m, 0) * 0.05m;

The same logic can be used in T-SQL:

ROUND(@mydecimal / 0.05, 0) * 0.05

I prefer this approach to the selected answer simply because you can directly see the precision used.

回答3:

Something like this should work for any step, not just 0.05:

private decimal RoundUp (decimal value, decimal step)
{
    var multiplicand = Math.Ceiling (value / step);
    return step * multiplicand;
}

回答4:

Math..::.Round Method (Decimal, Int32, MidpointRounding)

Rounds a double-precision floating-point value to the specified number of fractional digits. A parameter specifies how to round the value if it is midway between two other numbers.

   Math.Round(1.489,2,MidpointRounding.AwayFromZero)

回答5:

Duplicated here and here for ruby and python. It shouldn't be too different.

来源：https://stackoverflow.com/questions/1448458/how-to-round-decimal-value-up-to-nearest-0-05-value