【推荐】2019 Java 开发者跳槽指南.pdf(吐血整理) >>>
###刚刚遇到装饰器与闭包问题,这个有个小区分
- 闭包一
def count_outter():
L = []
def count_inner():
for i in range (1,5):
L.append(i)
return L
return count_inner
a = count_outter()
print(a)
print(a())
结果
<function count_outter.<locals>.count_inner at 0x10137a9d8>
[1, 2, 3, 4]
- 闭包二
def count():
fs = []
for i in range(1, 4):
def f():
return i*i
fs.append(f)
return fs
f1, f2, f3 = count()
结果
>>> f1()
9
>>> f2()
9
>>> f3()
9
- 闭包三
def count():
def f(j):
def g():
return j*j
return g
fs = []
for i in range(1, 4):
fs.append(f(i)) # f(i)立刻被执行,因此i的当前值被传入f()
return fs
结果
>>> f1, f2, f3 = count()
>>> f1()
1
>>> f2()
4
>>> f3()
9
- 装饰器一
import functools
def log(func):
@functools.wraps(func)
def wrapper(*args, **kw):
print('call %s():' % func.__name__)
return func(*args, **kw)
return wrapper
- 装饰器二:带参装饰器
import functools
def log(text):
def decorator(func):
@functools.wraps(func)
def wrapper(*args, **kw):
print('%s %s():' % (text, func.__name__))
return func(*args, **kw)
return wrapper
return decorator
####资料来自廖老师的教程
来源:oschina
链接:https://my.oschina.net/u/3019249/blog/782709