问题
I use the following code. It works fine on iOS 5, but in iOS 6 I didn't get the IP address.
#import <ifaddrs.h>
#import <arpa/inet.h>
-(NSString *)getIPAddress {
NSString *address = @"error";
struct ifaddrs *interfaces = NULL;
struct ifaddrs *temp_addr = NULL;
int success = 0;
// retrieve the current interfaces - returns 0 on success
success = getifaddrs(&interfaces);
if (success == 0) {
// Loop through linked list of interfaces
temp_addr = interfaces;
while(temp_addr != NULL) {
if(temp_addr->ifa_addr->sa_family == AF_INET) {
// Check if interface is en0 which is the wifi connection on the iPhone
if([[NSString stringWithUTF8String:temp_addr- >ifa_name]isEqualToString:@"en0"]) {
// Get NSString from C String
address = [NSString stringWithUTF8String:inet_ntoa(((struct sockaddr_in *)temp_addr->ifa_addr)->sin_addr)];
}
}
temp_addr = temp_addr->ifa_next;
}
}
// Free memory
freeifaddrs(interfaces);
return address;
}
Is there any problem with WiFi connections in iOS 6? It works well in iOS 5. Thank you.
回答1:
try this
- (void)viewDidLoad
{
[super viewDidLoad];
NSString *str =[self getIPAddress];
NSLog(@"%@",str);
// Do any additional setup after loading the view, typically from a nib.
}
-(NSString *)getIPAddress
{
struct ifaddrs *interfaces = NULL;
struct ifaddrs *temp_addr = NULL;
NSString *wifiAddress = nil;
NSString *cellAddress = nil;
NSString *addr;
if(!getifaddrs(&interfaces)) {
temp_addr = interfaces;
while(temp_addr != NULL) {
sa_family_t sa_type = temp_addr->ifa_addr->sa_family;
if(sa_type == AF_INET || sa_type == AF_INET6) {
NSString *name = [NSString stringWithUTF8String:temp_addr->ifa_name];
addr = [NSString stringWithUTF8String:inet_ntoa(((struct sockaddr_in *)temp_addr->ifa_addr)->sin_addr)];
if([name isEqualToString:@"en0"]) {
wifiAddress = addr;
} else
if([name isEqualToString:@"pdp_ip0"]) {
cellAddress = addr;
}
}
temp_addr = temp_addr->ifa_next;
}
// Free memory
freeifaddrs(interfaces);
}
return addr;
}
来源:https://stackoverflow.com/questions/15173291/in-ios6-how-to-get-the-ip-address