问题
for my work, i must to send multiples sms with an api and i want to put numbers in array from mysql like this :
(the numbers are in my database)
I want like this :
$list_num = array(
'0601020301','0601020302','0601020303','0601020304','0601020305','0601020306','0601020307','0601020308','0601020309','0601020310',
'0601020311','0601020312','0601020313','0601020314','0601020315','0601020316','0601020317','0601020318','0601020319','0601020320',
'0601020321','0601020322','0601020323','0601020324','0601020325','0601020326','0601020327','0601020328','0601020329','0601020330'
);
i have try this, but doesnt work :
$result = mysql_query("SELECT * FROM test");
if (!$result) {
die('Requête invalide : ' . mysql_error());
}
$a = array();
while ($row = mysql_fetch_assoc($result)) // moi je fais comme ca un mysql_fetch_*
{
$a[] = $row['numero'];
foreach ($a as $val) {
$ret .= "$val";
if ($ret == end($a))
//var_dump($val);
{
//echo "'".$val."'";
}
else
{
echo "'".$val."',";
}
}
}
Probably wrong method, i have search before here before, Thanks a lot.
回答1:
This should do the trick. You just need to adapt names/parameters to your needs. I used json, do something else if you need, or decode...
<?php
error_reporting(E_ALL);
ini_set('display_errors', 1);
include"config.inc.php";
$mysqli = mysqli_connect("$host", "$user", "$mdp", "$db");
if (mysqli_connect_errno()) { echo "Error connecting : " . mysqli_connect_error($mysqli); }
$query = " SELECT id_test, name_test, phone_test FROM tbl_tests ";
$stmt = $mysqli->prepare($query);
$results = $stmt->execute();
$stmt->bind_result($id_test, $name_test, $phone_test);
$stmt->store_result();
if ($stmt->num_rows > 0) {
$phones = array();
$phone = array();
while($stmt->fetch()){
echo"[ $id_test -> $name_test -> $phone_test ]<br />";
$phone = "$phone_test";
array_push($phones, $phone);
}
}
else
{ echo"[ no data ]"; }
//print_r($phones);
echo json_encode($phones);
?>
output : ["00544656347","0065465836","00656566745","0068456868","00626565064"]
EDIT: please As mysql_* was deprecated in PHP 5.5 (please refer to PHP doc) you should prefer PPS : Prepared Parameterized Statements. This will help Preventing SQL injection
回答2:
my script doesn't works with teh output json, however is a good trick. How to make like this :
$data = array(
array(
'number 1 from my database',
'number 2 from my database',
'number 3 from my database',
'number 4 from my database',
'number 5 from my database',
'number 6 from my database',
'number 7 from my database'
),
来源:https://stackoverflow.com/questions/43323372/list-number-in-array-php