“The operation is not valid for the state of the transaction” error and transaction scope

南笙酒味 提交于 2019-11-27 12:00:49

After doing some research, it seems I cannot have two connections opened to the same database with the TransactionScope block. I needed to modify my code to look like this:

public void MyAddUpdateMethod()
{
    using (TransactionScope Scope = new TransactionScope(TransactionScopeOption.RequiresNew))
    {
        using(SQLServer Sql = new SQLServer(this.m_connstring))
        {
            //do my first add update statement            
        }

        //removed the method call from the first sql server using statement
        bool DoesRecordExist = this.SelectStatementCall(id)
    }
}

public bool SelectStatementCall(System.Guid id)
{
    using(SQLServer Sql = new SQLServer(this.m_connstring))
    {
        //create parameters
    }
}

I also come across same problem, I changed transaction timeout to 15 minutes and it works. I hope this helps.

TransactionOptions options = new TransactionOptions();
options.IsolationLevel = System.Transactions.IsolationLevel.ReadCommitted;
options.Timeout = new TimeSpan(0, 15, 0);
using (TransactionScope scope = new TransactionScope(TransactionScopeOption.Required,options))
{
    sp1();
    sp2();
    ...

}

When I encountered this exception, there was an InnerException "Transaction Timeout". Since this was during a debug session, when I halted my code for some time inside the TransactionScope, I chose to ignore this issue.

When this specific exception with a timeout appears in deployed code, I think that the following section in you .config file will help you out:

<system.transactions> 
        <machineSettings maxTimeout="00:05:00" /> 
</system.transactions>

I've encountered this error when my Transaction is nested within another. Is it possible that the stored procedure declares its own transaction or that the calling function declares one?

For me, this error came up when I was trying to rollback a transaction block after encountering an exception, inside another transaction block.

All I had to do to fix it was to remove my inner transaction block.

Things can get quite messy when using nested transactions, best to avoid this and just restructure your code.

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