Use sed to delete a matched regexp and the line (or two) underneath it

问题

OK I found this question:

How do I delete a matching line, the line above and the one below it, using sed?

and just spent the last hour trying to write something that will match a string and delete the line containing the string and the line beneath it (or a variant - delete 2 lines beneath it).

I feel I'm now typing random strings. Please somebody help me.

回答1:

If I've understood that correctly, to delete match line and one line after

/matchstr/{N;d;}

Match line and two lines after

/matchstr/{N;N;d;}

• N brings in the next line
• d - deletes the resulting single line

回答2:

you can use awk. eg search for the word "two" and skip 2 lines after it

$ cat file
one
two
three
four
five
six
seven
eight
$ awk -vnum=2 '/two/{for(i=0;i<=num;i++)getline}1' file
one
five
six
seven
eight

来源：https://stackoverflow.com/questions/2061131/use-sed-to-delete-a-matched-regexp-and-the-line-or-two-underneath-it