Trouble unpacking list in a customized way

问题

I'm trying to unpack some list which I've yielded within get_item() function. I know I can get desired result If I used return instead of yield.

I've tried:

def get_item():
    yield ["k","y","t"]

if __name__ == '__main__':
    for item in get_item():
        print(item)

Output I'm getting:

['k', 'y', 't']

Output I wanna get:

k
y
t

What possible change should I bring about to get the desired result keeping yield as it is?

回答1:

As of Python 3.3, you can use yield from:

def get_item():
    yield from ["k","y","t"]

if __name__ == '__main__':
    for item in get_item():
        print(item)

Output:

k
y
t

yield from is a new trick introduced in Python 3.3, a short part of it:

For simple iterators, yield from iterable is essentially just a shortened form of for item in iterable: yield item:

^{(emphasis mine)}

回答2:

Desired result you can get with * operator:

def get_item():
    yield ["k","y","t"]

if __name__ == '__main__':
    print('\n'.join(*get_item()))

Prints:

k
y
t

回答3:

Try Below:

def get_item():
    for _ in ["k","y","t"]:
        yield  _

if __name__ == '__main__':
    for item in get_item():
        print(item)

来源：https://stackoverflow.com/questions/56985094/trouble-unpacking-list-in-a-customized-way