Listing the contents of a ZIP file

问题

Following an example of tech-recipes I have managed to list the contents of a ZIP file (using 7-Zip:

FOR /F "tokens=* delims=" %%A in ('dir /b /s *.zip') do (7z.exe l -r "%%A" >> listing.txt)

However, this just dumps out the entire directory structure of the ZIP file into a text file (called listing.txt).

I only want to list the directory names of the highest level directories e.g.

Example.Zip

7-Zip 9.20  Copyright (c) 1999-2010 Igor Pavlov  2010-11-18

Listing archive: C:\Users\Test\Desktop\7zip\Demo.zip

--
Path = C:\Users\Test\Desktop\7zip\Demo.zip
Type = zip
Physical Size = 1252

   Date      Time    Attr         Size   Compressed  Name
------------------- ----- ------------ ------------  ------------------------
2013-04-24 13:12:26 D....            0            0  Directory Three\Sub Folder One
2013-04-24 13:13:00 D....            0            0  Directory Three\Sub Folder Three
2013-04-24 13:12:54 D....            0            0  Directory Three\Sub Folder Two
2013-04-24 13:12:26 D....            0            0  Directory Two\Sub Folder One
2013-04-24 13:13:00 D....            0            0  Directory Two\Sub Folder Three
2013-04-24 13:12:54 D....            0            0  Directory Two\Sub Folder Two
2013-04-24 13:12:26 D....            0            0  Directory One\Sub Folder One
2013-04-24 13:13:00 D....            0            0  Directory One\Sub Folder Three
2013-04-24 13:12:54 D....            0            0  Directory One\Sub Folder Two
------------------- ----- ------------ ------------  ------------------------
                                     0            0  0 files, 9 folders

I would only want the text file to contain:

Directory One
Directory Two
Directory Three

Can anyone suggest how I could achieve this?

回答1:

7z doesn't seem to have builtin key for this, however you can do some batch scripting (this one searches for slash in file name and displays line if slash not found) :

7z.exe l -r archive.zip > lines.txt

@echo off

setlocal ENABLEDELAYEDEXPANSION

for /f "tokens=*" %%a in (lines.txt) do (
  set line=%%a
  set srch=!line:\=!
  if "!line!" == "!srch!" (
     echo !line!
  )
)

回答2:

7z.exe l -r "File.7z" | FINDSTR "[0-9].D....\>" | FIND /V "\"

With the first Findstr we filter the output getting a list of only dirs ("D" attribute).

With the second find we delete from the output the paths containing backslashes (Folder\Subfolder).

How to use it with a amount of zips:

@echo off

(For /R %%# in (*.zip) do (

    Echo File: "%%#" | MORE

    For /F "Tokens=5,*" %%A in (
        '7z.exe l -r "%%#" ^| FINDSTR "[0-9].D....\>" ^| FIND /V "\"'
    ) do (
        Set /A "Num+=1"
        Call Echo %%NUM%%.0: %%B
    )

    Set /A "Num=0"
    Echo+

))>"listing.txt"

Pause&Exit

Tested structure:

   Date      Time    Attr         Size   Compressed  Name
------------------- ----- ------------ ------------  ------------------------
2013-04-24 13:02:29 ....A          274          167  ..bat
2013-04-24 13:02:29 ....A          274               1\2\2.bat
2013-04-24 13:02:29 ....A          274               a\b\c\c.bat
2013-04-24 13:12:45 D....            0            0  a\b\c
2013-04-24 13:12:37 D....            0            0  a\b
2013-04-24 13:12:33 D....            0            0  a
2013-04-24 13:12:50 D....            0            0  1\2
2013-04-24 13:12:24 D....            0            0  1
------------------- ----- ------------ ------------  ------------------------
                                   822          167  3 files, 5 folders

Output received:

File: "C:\Users\Administrador\Desktop\Nueva carpeta\x.7z" 

1.0: a
2.0: 1

来源：https://stackoverflow.com/questions/16188135/listing-the-contents-of-a-zip-file

标签

batch-file

zip

7zip