how to get only not null element count in array php

问题

i want to get only not null values count in that array , if i use count() or sizeof it will get the null indexes also .

in my case

i have an array like this Array ( [0] => )

the count is 1 . but i want to get the not null count , inthis case it should be 0 , how can i do this , please help............................

回答1:

simply use array_filter() without callback

print_r(array_filter($entry));

回答2:

$count = count(array_filter($array));

array_filter will remove any entries that evaluate to false, such as null, the number 0 and empty strings. If you want only null to be removed, you need:

$count = count(array_filter($array,create_function('$a','return $a !== null;')));

回答3:

something like...

$count=0;
foreach ($array as $k => $v)
{
    if (!empty($v))
    {
        $count++;
    }
}

should do the trick. you could also wrap it in a function like:

function countArray($array)
{
$count=0;
foreach ($array as $k => $v)
{
    if (!empty($v))
    {
        $count++;
    }
}
return $count;

}

echo countArray($array);

回答4:

although i'm not that good with PHP i think you should programatically remove empty elements from the array the link might help

回答5:

One option is

echo "Count is ".count(array_filter($array_with_nulls, 'strlen'));

If you don't count empty and nulls values you can do this

echo "Count is ".count(array_filter($array_with_nulls));

In this blog you can see a little more info

http://briancray.com/2009/04/25/remove-null-values-php-arrays/

来源：https://stackoverflow.com/questions/7672562/how-to-get-only-not-null-element-count-in-array-php

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