问题
I cannot find the answer to this seemingly simple question anywhere.
Does the following C++ function use RTTI? It certainly doesn't have to, but I was wondering if there is a guarantee that typeid will be determined at compile time.
template <typename T>
const char *getName()
{
return typeid(T).name(); // Resolved at compile time?
}
回答1:
Since typeid
is applied to a type rather than an object, there is no runtime type information, so that overhead won't be a problem.
On the other hand: as far as I can see, the standard makes no requirements regarding when the value will be determined, so there's no guarantee that there's no runtime overhead.
Edit:
Of course, the fact that there's (possibly) no guarantee doesn't mean that it's not a reasonable assumption.
I can't imagine that anyone would write a compiler that didn't evaluate typeid(T)
at compile time.
回答2:
As I mentioned in a comment, the "Notes" section regarding typeid()
on cpp reference says:
When applied to an expression of polymorphic type, evaluation of a typeid expression may involve runtime overhead (a virtual table lookup), otherwise typeid expression is resolved at compile time.
来源:https://stackoverflow.com/questions/18781832/does-typeidt-get-evaluated-at-run-time-or-compile-time