问题
I have found many snippets here and in other places that answer parts of this question. I have even managed to do this in many steps in an inefficient manner. If it is possible, I would really like to find single lines of execution that will perform this task, rather than having to assign to a variable and copy it a few times to perform the task.
e.g.
executeToVar ()
{
# Takes Arg1: NAME OF VARIABLE TO STORE IN
# All Remaining Arguments Are Executed
local STORE_INvar="${1}" ; shift
eval ${STORE_INvar}=\""$( "$@" 2>&1 )"\"
}
Overall does work, i.e. $ executeToVar SOME_VAR ls -l * #
will actually fill SOME_VAR
with the output of the execution of the ls -l *
command that is taken from the rest of the arguments. However, if the command was to output empty lines at the end, (for e.g. - echo -e -n '\n\n123\n456\n789\n\n'
which should have 2 x new lines at the start and the end ) these are stripped by bash's sub-execution process. I have seen in other posts similar to this that this has been solved by adding a token 'x' to the end of the stream, e.g. turning the sub-execution into something like:
eval ${STORE_INvar}=\""$( "$@" 2>&1 ; echo -n x )"\" # <-- ( Add echo -n x )
# and then if it wasn't an indirect reference to a var:
STORE_INvar=${STORE_INvar%x}
# However no matter how much I play with:
eval "${STORE_INvar}"=\""${STORE_INvar%x}"\"
# I am unable to indirectly remove the x from the end.
Anyway, I also need 2 x other variants on this, one that assigns the STDIN stream
to the var and one that assigns the contents of a file to the var which I assume will be variations of this involving $( cat ${1} )
, or maybe $( cat ${1:--} )
to give me a '-' if no filename. But, none of that will work until I can sort out the removal of the x that is needed to ensure accurate assignment of multi line variables.
I have also tried (but to no avail):
IFS='' read -d '' "${STORE_INvar}" <<<"$( $@ ; echo -n x )"
eval \"'${STORE_INvar}=${!STORE_INvar%x}'\"
回答1:
This is close to optimal -- but drop the eval
.
executeToVar() { local varName=$1; shift; printf -v "$1" %s "$("$@")"; }
The one problem this formulation still has is that $()
strips trailing newlines. If you want to prevent that, you need to add your own trailing character inside the subshell, and strip it off yourself.
executeToVar() {
local varName=$1; shift;
local val="$(printf %s x; "$@"; printf %s x)"; val=${val#x}
printf -v "$varName" %s "${val%x}"
}
If you want to read all content from stdin into a variable, this is particularly easy:
# This requires bash 4.1 for automatic fd allocation
readToVar() {
if [[ $2 && $2 != "-" ]]; then
exec {read_in_fd}<"$2" # copy from named file
else
exec {read_in_fd}<&0 # copy from stdin
fi
IFS= read -r -d '' "$1" <&$read_in_fd # read from the FD
exec {read_in_fd}<&- # close that FD
}
...used as:
readToVar var < <( : "run something here to read its output byte-for-byte" )
...or...
readToVar var filename
Testing these:
bash3-3.2$ executeToVar var printf '\n\n123\n456\n789\n\n'
bash3-3.2$ declare -p var
declare -- var="
123
456
789
"
...and...
bash4-4.3$ readToVar var2 < <(printf '\n\n123\n456\n789\n\n')
bash4-4.3$ declare -p var2
declare -- var2="
123
456
789
"
回答2:
what'w wrong with storing in a file:
$ stuffToFile filename $(stuff)
where "stuffToFile" tests for a. > 1 argument, b. input on a pipe
$ ... commands ... | stuffToFile filename
and
$ stuffToFile filename < another_file
where "stoffToFile" is a function:
function stuffToFile
{
[[ -f $1 ]] || { echo $1 is not a file; return 1; }
[[ $# -lt 2 ]] && { cat - > $1; return; }
echo "$*" > $1
}
so, if "stuff" has leading and trailing blank lines, then you must:
$ stuff | stuffToFile filename
来源:https://stackoverflow.com/questions/29900839/how-do-i-indirectly-assign-a-variable-in-bash-to-take-multi-line-data-from-both