问题
I have this:
class MyClass:
"""A simple example class"""
i = 12345
def f(self):
print i # self.i will work just fine
return 'hello world'
When I do:
>>> x = MyClass()
>>>
>>> x.f()
I get an error, as expected.
My question is:
Why do I get the error?
Why is there no namespace between the namespace of the function(or method) definition and the global namespace of the module containing the class?
Is there any other way to reference i inside f in this case other than using self?
回答1:
- You've got an error because
print i
is trying to print a global (for the module) variablei
. If you want to use the member of the class you should writeself.i
. - Because Guido Van Rossum decided not to use namespaces. Actually, I don't know how to answer anymore.
- Yes, but no. Yes, because you can use "reflection" (I can't remember how it is called in python) and access any member of the class. No, because using
self
is the only usable way.
来源:https://stackoverflow.com/questions/14299013/namespaces-within-a-python-class