print address of array of char

问题

int *i = new int(1);
cout << i << endl; 

Will print the address of the integer.

    char *c="cstring";
    cout << c << endl;
    cout << &(*c) << endl;

Will both print "cstring". I guess this behavior can simply be explained with the implementation of ostream& operator<< (ostream& out, const char* s ); in the IOstream Library.

But what to do if you actually want to print the address of the data c refers to?

回答1:

cout << reinterpret_cast<void*>(c) << endl;

or just

cout << (void*)c << endl;

回答2:

Try casting it as a const void* :

cout << static_cast<const void*>(c) << endl;

回答3:

How about just

cout << &c << endl;

Works for me :)

来源：https://stackoverflow.com/questions/11537621/print-address-of-array-of-char