问题
I have an array of double pointers, but every time I try do print one of the values the address gets printed. How do I print the actual value?
cout << arr[i] ? cout << &arr[i] ? they both print the address
Does anyone know?
回答1:
If it's really an array of (initialized) double pointers, i.e.:
double *arr[] = ...
// Initialize individual values
all you need is:
cout << *arr[i];
回答2:
cout << *(arr[i]) will print the value.
回答3:
cout << *(arr[i]);
回答4:
If "arr" is declared as
double* arr[..];
Then you would use:
cout << *(arr[i])
来源：https://stackoverflow.com/questions/2485565/c-print-value-of-a-pointer