问题
<field name="http.user_agent" showname="User-Agent: CORE/6.506.4.1 OpenCORE/2.02 (Linux;Android 2.2)\r\n" size="62" pos="542" show="CORE/6.506.4.1 OpenCORE/2.02 (Linux;Android 2.2)" value="557365722d4167656e743a20434f52452f362e3530362e342e31204f70656e434f52452f322e303220284c696e75783b416e64726f696420322e32290d0a"/>
<field name="http.user_agent" showname="User-Agent: HTC Streaming Player htc_wwe / 1.0 / htc_vivo / 2.3.5\r\n" size="67" pos="570" show="HTC Streaming Player htc_wwe / 1.0 / htc_vivo / 2.3.5" value="557365722d4167656e743a204854432053747265616d696e6720506c61796572206874635f777765202f20312e30202f206874635f7669766f202f20322e332e350d0a"/>
<field name="http.user_agent" showname="User-Agent: AppleCoreMedia/1.0.0.8C148 (iPad; U; CPU OS 4_2_1 like Mac OS X; sv_se)\r\n" size="85" pos="639" show="AppleCoreMedia/1.0.0.8C148 (iPad; U; CPU OS 4_2_1 like Mac OS X; sv_se)" value="557365722d4167656e743a204170706c65436f72654d656469612f312e302e302e38433134382028695061643b20553b20435055204f5320345f325f31206c696b65204d6163204f5320583b2073765f7365290d0a"/>
The samples of the urls I've got are listed above. I am wondering if there is any module in Python which I can use to parse the user-agent. I want to get the output from these samples like:
Android
HTC Streaming player
ipad
and if it is a PC user, I want to get the web browser type.
回答1:
There is a library called httpagentparser for that:
import httpagentparser
>>> s = "Mozilla/5.0 (X11; U; Linux i686; en-US) AppleWebKit/532.9 (KHTML, like Gecko) Chrome/5.0.307.11 Safari/532.9"
>>> print httpagentparser.simple_detect(s)
('Linux', 'Chrome 5.0.307.11')
>>> print httpagentparser.detect(s)
{'os': {'name': 'Linux'},
'browser': {'version': '5.0.307.11', 'name': 'Chrome'}}
回答2:
Werkzeug has a user agent parser built in.
http://werkzeug.pocoo.org/docs/quickstart/?highlight=user_agent#header-parsing
回答3:
You can try to write your own with regular expression : http://docs.python.org/library/re.html or take a look at this : http://pypi.python.org/pypi/httpagentparser
来源:https://stackoverflow.com/questions/9209377/how-to-parse-user-agent-string-python