How to check if a property is virtual with reflection?

问题

Given an object, how can I tell if that object has virtual properties?

var entity = repository.GetByID(entityId);

I tried looking in:

PropertyInfo[] properties = entity.GetType().GetProperties();

But couldn't discern if any of the properties would indicate virtual.

回答1:

PropertyInfo[] properties = entity.GetType().GetProperties()
    .Where(p => p.GetMethod.IsVirtual).ToArray();

Or, for .NET 4 and below:

PropertyInfo[] properties = entity.GetType().GetProperties()
    .Where(p => p.GetGetMethod().IsVirtual).ToArray();

That will get a list of public virtual properties.

It won't work for write-only properties. If it needs to, you can check CanRead and CanWrite manually, and read the appropriate method.

For example:

PropertyInfo[] properties = entity.GetType().GetProperties()
    .Where(p => (p.CanRead ? p.GetMethod : p.SetMethod).IsVirtual).ToArray();

You could also just grab the first accessor:

PropertyInfo[] properties = entity.GetType().GetProperties()
    .Where(p => p.GetAccessors()[0].IsVirtual).ToArray();

回答2:

Checking only IsVirtual of property's accessor will give you also interface properties that are not declared virtual in your class. If by "virtual properties" you mean properties that you can override in derived class you should also check IsFinal (sealed):

var accessor = typeof(MyType).GetProperty("MyProp").GetAccessors()[0];
var isVirtual = accessor.IsVirtual && ! accessor.IsFinal;

Check this sample app:

using System;

namespace VirtualPropertyReflection
{
    interface I
    {
        int P1 { get; set; }
        int P2 { get; set; }
    }

    class A : I
    {
        public int P1 { get; set; }
        public virtual int P2 { get; set; }

        static void Main()
        {
            var p1accessor = typeof(A).GetProperty("P1").GetAccessors()[0];
            Console.WriteLine(p1accessor.IsVirtual); // True
            Console.WriteLine(p1accessor.IsFinal); // True

            var p2accessor = typeof(A).GetProperty("P2").GetAccessors()[0];
            Console.WriteLine(p2accessor.IsVirtual); // True
            Console.WriteLine(p2accessor.IsFinal); // False
        }
    }
}

See this answer.

回答3:

try with

typeof(YourClass).GetProperty("YouProperty").GetGetMethod().IsVirtual;

回答4:

Use the GetAccessors method, for example for the first property:

Get accessor:

properties[0].GetAccessors()[0].IsVirtual

Set accessor:

properties[0].GetAccessors()[1].IsVirtual

回答5:

This is a little tricky, because a property can be read-only, write-only, or read/write. Therefore, you need to check both underlying methods for being virtual, like this:

PropertyInfo pi = ...
var isVirtual = (pi.CanRead && pi.GetMethod.IsVirtual)
             || (pi.CanWrite && pi.SetMethod.IsVirtual);

回答6:

IsVirtual alone didn't work for me. It was telling me that all my non-virtual non-nullable properties were virtual. I had to use a combination of IsFinal and IsVirtual

Here's what I ended up with:

PropertyInfo[] nonVirtualProperties = myType.GetProperties().Where(x => x.GetAccessors()[0].IsFinal || !x.GetAccessors()[0].IsVirtual).ToArray();

PropertyInfo[] virtualProperties = myType.GetProperties().Where(x => !x.GetAccessors()[0].IsFinal && x.GetAccessors()[0].IsVirtual).ToArray();

来源：https://stackoverflow.com/questions/12305945/how-to-check-if-a-property-is-virtual-with-reflection

标签

reflection

virtual