问题
I am working on heat map with a unique dataset. The dataset consists of a symbol. Here is the example of my dataset 1q.txt
one two three
2009 0/0 1 0/0 1 0/0 1
2010 0/0 1 0/0 1 0/0 1
2011 0/0 1 0/0 1 6/179.5 1
2012 0/0 1 2/0.4 1 11/83.0 1
2013 7/0.8 1 7/21.3 1 17/268.5 1
2014 1/3.5 1 4/7.7 1 9/37.9 1
and here is my gnuplot script
set term pos eps font 20
unset colorbox
unset key
set nocbtics
set cblabel "Score"
set cbtics scale 0
set cbrange [ 0.00000 : 110.00000 ] noreverse nowriteback
set palette defined ( 0.0 "#FFFFFF",\
1 "#FFCCCC",\
2 "#FF9999 ",\
3 "#FF6666")
set size 1, 0.5
set output '1q.eps'
YTICS="`awk 'BEGIN{getline}{printf "%s ",$1}' '1q.dat'`"
XTICS="`head -1 '1q.dat'`"
set for [i=1:words(XTICS)] xtics ( word(XTICS,i) i-1 )
set for [i=1:words(YTICS)] ytics ( word(YTICS,i) i-1 )
set for [i=1:words(XTICS)] xtics ( word(XTICS,i) 2*i-1 )
plot "<awk '{$1=\"\"}1' '1q.dat' | sed '1 d'" matrix every 2::1 w image, \
'' matrix using ($1+1):2:(sprintf('%.f', $3)) every 2 with labels
What I'm trying to do here is I want to displaying "0/0" as a label in the heatmap and the integer number as a heatmap color.
The problem that I face here is the gnuplot only take a number before "/" and ignore the other one.
Here is the result of my current plot.
How to make the heatmap show a lable like "1/3.5" and have color based on the integer number.
回答1:
There is no need to usesprintf
at all. Simply use stringcolumn
to get the raw content of a column as saved in the data file:
plot "<awk '{$1=\"\"}1' '1q.dat' | sed '1 d'" matrix every 2::1 w image, \
'' matrix using ($1+1):2:(stringcolumn(3)) every 2 with labels
来源:https://stackoverflow.com/questions/34504450/print-sprintf-error-while-the-input-is-a-string-which-consist-of-symbol-in-heatm