How can I use Swift’s Codable to encode into a dictionary?

Question

I have a struct that implements Swift 4’s Codable. Is there a simple built-in way to encode that struct into a dictionary?

let struct = Foo(a: 1, b: 2)
let dict = something(struct)
// now dict is ["a": 1, "b": 2]

Answer 1

If you don't mind a bit of shifting of data around you could use something like this:

extension Encodable {
  func asDictionary() throws -> [String: Any] {
    let data = try JSONEncoder().encode(self)
    guard let dictionary = try JSONSerialization.jsonObject(with: data, options: .allowFragments) as? [String: Any] else {
      throw NSError()
    }
    return dictionary
  }
}

Or an optional variant

extension Encodable {
  var dictionary: [String: Any]? {
    guard let data = try? JSONEncoder().encode(self) else { return nil }
    return (try? JSONSerialization.jsonObject(with: data, options: .allowFragments)).flatMap { $0 as? [String: Any] }
  }
}

Assuming Foo conforms to Codable or really Encodable then you can do this.

let struct = Foo(a: 1, b: 2)
let dict = try struct.asDictionary()
let optionalDict = struct.dictionary

If you want to go the other way(init(any)), take a look at this Init an object conforming to Codable with a dictionary/array

Answer 2

Here are simple implementations of DictionaryEncoder / DictionaryDecoder that wrap JSONEncoder, JSONDecoder and JSONSerialization, that also handle encoding / decoding strategies…

class DictionaryEncoder {

    private let encoder = JSONEncoder()

    var dateEncodingStrategy: JSONEncoder.DateEncodingStrategy {
        set { encoder.dateEncodingStrategy = newValue }
        get { return encoder.dateEncodingStrategy }
    }

    var dataEncodingStrategy: JSONEncoder.DataEncodingStrategy {
        set { encoder.dataEncodingStrategy = newValue }
        get { return encoder.dataEncodingStrategy }
    }

    var nonConformingFloatEncodingStrategy: JSONEncoder.NonConformingFloatEncodingStrategy {
        set { encoder.nonConformingFloatEncodingStrategy = newValue }
        get { return encoder.nonConformingFloatEncodingStrategy }
    }

    var keyEncodingStrategy: JSONEncoder.KeyEncodingStrategy {
        set { encoder.keyEncodingStrategy = newValue }
        get { return encoder.keyEncodingStrategy }
    }

    func encode<T>(_ value: T) throws -> [String: Any] where T : Encodable {
        let data = try encoder.encode(value)
        return try JSONSerialization.jsonObject(with: data, options: .allowFragments) as! [String: Any]
    }
}

class DictionaryDecoder {

    private let decoder = JSONDecoder()

    var dateDecodingStrategy: JSONDecoder.DateDecodingStrategy {
        set { decoder.dateDecodingStrategy = newValue }
        get { return decoder.dateDecodingStrategy }
    }

    var dataDecodingStrategy: JSONDecoder.DataDecodingStrategy {
        set { decoder.dataDecodingStrategy = newValue }
        get { return decoder.dataDecodingStrategy }
    }

    var nonConformingFloatDecodingStrategy: JSONDecoder.NonConformingFloatDecodingStrategy {
        set { decoder.nonConformingFloatDecodingStrategy = newValue }
        get { return decoder.nonConformingFloatDecodingStrategy }
    }

    var keyDecodingStrategy: JSONDecoder.KeyDecodingStrategy {
        set { decoder.keyDecodingStrategy = newValue }
        get { return decoder.keyDecodingStrategy }
    }

    func decode<T>(_ type: T.Type, from dictionary: [String: Any]) throws -> T where T : Decodable {
        let data = try JSONSerialization.data(withJSONObject: dictionary, options: [])
        return try decoder.decode(type, from: data)
    }
}

Usage is similar to JSONEncoder / JSONDecoder…

let dictionary = try DictionaryEncoder().encode(object)

and

let object = try DictionaryDecoder().decode(Object.self, from: dictionary)

---

For convenience, I've put this all in a repo… https://github.com/ashleymills/SwiftDictionaryCoding

Answer 3

I have create a library called CodableFirebase and it's initial purpose was to use it with Firebase Database, but it does actually what you need: it creates a dictionary or any other type just like in JSONDecoder but you don't need to do the double conversion here like you do in other answers. So it would look something like:

import CodableFirebase

let model = Foo(a: 1, b: 2)
let dict = try! FirebaseEncoder().encode(model)

Answer 4

I'm not sure if it's the best way but you definitely can do something like:

struct Foo: Codable {
    var a: Int
    var b: Int

    init(a: Int, b: Int) {
        self.a = a
        self.b = b
    }
}

let foo = Foo(a: 1, b: 2)
let dict = try JSONDecoder().decode([String: Int].self, from: JSONEncoder().encode(foo))
print(dict)

Answer 5

There is no built in way to do that. As answered above if you have no performance issues then you can accept the JSONEncoder + JSONSerialization implementation.

But I would rather go the standard library's way to provide an encoder/decoder object.

class DictionaryEncoder {
    private let jsonEncoder = JSONEncoder()

    /// Encodes given Encodable value into an array or dictionary
    func encode<T>(_ value: T) throws -> Any where T: Encodable {
        let jsonData = try jsonEncoder.encode(value)
        return try JSONSerialization.jsonObject(with: jsonData, options: .allowFragments)
    }
}

class DictionaryDecoder {
    private let jsonDecoder = JSONDecoder()

    /// Decodes given Decodable type from given array or dictionary
    func decode<T>(_ type: T.Type, from json: Any) throws -> T where T: Decodable {
        let jsonData = try JSONSerialization.data(withJSONObject: json, options: [])
        return try jsonDecoder.decode(type, from: jsonData)
    }
}

You can try it with following code:

struct Computer: Codable {
    var owner: String?
    var cpuCores: Int
    var ram: Double
}

let computer = Computer(owner: "5keeve", cpuCores: 8, ram: 4)
let dictionary = try! DictionaryEncoder().encode(computer)
let decodedComputer = try! DictionaryDecoder().decode(Computer.self, from: dictionary)

I am force-trying here to make the example shorter. In production code you should handle the errors appropriately.

Answer 6

let dict = try JSONSerialization.jsonObject(with: try JSONEncoder().encode(struct), options: []) as? [String: Any]

Answer 7

In some project, i'm used the swift reflection. But be careful, nested codable objects, are not mapped also there.

let dict = Dictionary(uniqueKeysWithValues: Mirror(reflecting: foo).children.map{ ($0.label!, $0.value) })

Answer 8

I definitely think that there's some value in just being able to use Codable to encode to/from dictionaries, without the intention of ever hitting JSON/Plists/whatever. There are plenty of APIs which just give you back a dictionary, or expect a dictionary, and it's nice to be able to interchange them easily with Swift structs or objects, without having to write endless boilerplate code.

I've been playing round with some code based on the Foundation JSONEncoder.swift source (which actually does implement dictionary encoding/decoding internally, but doesn't export it).

The code can be found here: https://github.com/elegantchaos/DictionaryCoding

It's still quite rough, but I've expanded it a bit so that, for example, it can fill in missing values with defaults when decoding.

Answer 9

I have modified the PropertyListEncoder from the Swift project into a DictionaryEncoder, simply by removing the final serialisation from dictionary into binary format. You can do the same yourself, or you can take my code from here

It can be used like this:

do {
    let employeeDictionary: [String: Any] = try DictionaryEncoder().encode(employee)
} catch let error {
    // handle error
}

Answer 10

I wrote a quick gist to handle this (not using the Codable protocol). Be careful, it doesn't type-check any values and doesn't work recursively on values that are encodable.

class DictionaryEncoder {
    var result: [String: Any]

    init() {
        result = [:]
    }

    func encode(_ encodable: DictionaryEncodable) -> [String: Any] {
        encodable.encode(self)
        return result
    }

    func encode<T, K>(_ value: T, key: K) where K: RawRepresentable, K.RawValue == String {
        result[key.rawValue] = value
    }
}

protocol DictionaryEncodable {
    func encode(_ encoder: DictionaryEncoder)
}

Answer 11

There no straight forward way of doing this in Codable. You need to implement Encodable/Decodable protocol for your struct. For your example, you might need to write as below

typealias EventDict = [String:Int]

struct Favorite {
    var all:EventDict
    init(all: EventDict = [:]) {
        self.all = all
    }
}

extension Favorite: Encodable {
    struct FavoriteKey: CodingKey {
        var stringValue: String
        init?(stringValue: String) {
            self.stringValue = stringValue
        }
        var intValue: Int? { return nil }
        init?(intValue: Int) { return nil }
    }

    func encode(to encoder: Encoder) throws {
        var container = encoder.container(keyedBy: FavoriteKey.self)

        for eventId in all {
            let nameKey = FavoriteKey(stringValue: eventId.key)!
            try container.encode(eventId.value, forKey: nameKey)
        }
    }
}

extension Favorite: Decodable {

    public init(from decoder: Decoder) throws {
        var events = EventDict()
        let container = try decoder.container(keyedBy: FavoriteKey.self)
        for key in container.allKeys {
            let fav = try container.decode(Int.self, forKey: key)
            events[key.stringValue] = fav
        }
        self.init(all: events)
    }
}

Answer 12

I have made a pod here https://github.com/levantAJ/AnyCodable to facilitate decode and encode [String: Any] and [Any]

pod 'DynamicCodable', '1.0'

And you are able to decode & encode [String: Any] and [Any]

import DynamicCodable

struct YourObject: Codable {
    var dict: [String: Any]
    var array: [Any]
    var optionalDict: [String: Any]?
    var optionalArray: [Any]?

    enum CodingKeys: String, CodingKey {
        case dict
        case array
        case optionalDict
        case optionalArray
    }

    init(from decoder: Decoder) throws {
        let values = try decoder.container(keyedBy: CodingKeys.self)
        dict = try values.decode([String: Any].self, forKey: .dict)
        array = try values.decode([Any].self, forKey: .array)
        optionalDict = try values.decodeIfPresent([String: Any].self, forKey: .optionalDict)
        optionalArray = try values.decodeIfPresent([Any].self, forKey: .optionalArray)
    }

    func encode(to encoder: Encoder) throws {
        var container = encoder.container(keyedBy: CodingKeys.self)
        try container.encode(dict, forKey: .dict)
        try container.encode(array, forKey: .array)
        try container.encodeIfPresent(optionalDict, forKey: .optionalDict)
        try container.encodeIfPresent(optionalArray, forKey: .optionalArray)
    }
}

Answer 13

If you're using SwiftyJSON, you could do something like this:

JSON(data: JSONEncoder().encode(foo)).dictionaryObject

Note: You can also pass this dictionary as parameters to Alamofire requests.

Answer 14

Come to think of it, the question does not have an answer in the general case, since the Encodable instance may be something not serializable into a dictionary, such as an array:

let payload = [1, 2, 3]
let encoded = try JSONEncoder().encode(payload) // "[1,2,3]"

Other than that, I have written something similar as a framework.