Iterate through a Namespace

问题

I have got a namespace looking like this :

Namespace(aTQ=None, bE=None, bEQ=None, b=None, bQ=None, c=None, c=None, cJ=None, d=None, g=None, jR=['xx', '015'], lC=None, l=None)

How can I iterate through it so I can find and replace the 'xx' value for the "jR" key in place ?

回答1:

I'm not sure what you know in advance, (the name jR, or only that one name has a not None value) but you can try using vars() which, like __dict__ should be a dict that has the names in your namespace as its keys. So if you have the string 'jR' somewhere,

vars()['jR'] = vars()['jR'][0]

likewise, you can get the same dict using namespace.__dict__ instead of vars()

will leave you with the first value in ['xx','015'] as the only value for jR.

EDIT: To be clear, since vars() and __dict__ both return dicts, you can iterate through them as:

for k in namespace.__dict__:
    if namespace.__dict__[k] is not None:
        <<do something>>

来源：https://stackoverflow.com/questions/14865961/iterate-through-a-namespace