Sum of all number combinations excluding repetition Excel

问题

this top voted answer Sum all combinations Excel or Google Spreadsheets is close to what I need - however I require a solution where it keeps the combinations in order and excludes repetition based on this order. i.e. a data set of 1 2 3 4 would show the product of:

1 1+2 1+3 1+4 1+2+3 1+2+4 1+3+4 1+2+3+4

2 2+3 2+4 2+3+4

3 3+4

4

i.e

1 3 4 5 6 10

2 5 6

3 7

4

Is this possible in Google Sheets / Excel without a script?

Thanks

回答1:

Here's a formula to display the sums in order

=ArrayFormula(sort(" "&transpose(split(SUBSTITUTE(substitute(textjoin("+",true,{if(mod(int(row(A1:A15)/(2^(column(A1:D1)-1))),2)=0,"",column(A1:D1)),B1:B15&";"}),"+;",";"),";+",";"),";")),1,true))

This formula will give the sum totals in the order that they are generated, but then it would have to be combined with the first formula to get them in the right order

=ArrayFormula(mmult(if(mod(int(row(A1:A15)/(2^(column(A1:D1)-1))),2)=0,0,column(A1:D1)),transpose(column(A1:D1))^0))

Giving this

=ArrayFormula(sort({" "&transpose(split(SUBSTITUTE(substitute(textjoin("+",true,{if(mod(int(row(A1:A15)/(2^(column(A1:D1)-1))),2)=0,"",column(A1:D1)),B1:B15&";"}),"+;",";"),";+",";"),";")),ArrayFormula(mmult(if(mod(int(row(A1:A15)/(2^(column(A1:D1)-1))),2)=0,0,column(A1:D1)),transpose(column(A1:D1))^0))},1,true))

Here's how it would look if you used actual values rather than column numbers

=ArrayFormula(sort({" "&transpose(split(SUBSTITUTE(substitute(textjoin("+",true,{if(mod(int(row(A1:A15)/(2^(column(A1:D1)-1))),2)=0,"",column(A1:D1)),if(row(A1:A15)>0,";")}),"+;",";"),";+",";"),";")),ArrayFormula(mmult(if(mod(int(row(A1:A15)/(2^(column(A1:D1)-1))),2)=0,0,A1:D1),transpose(column(A1:D1))^0))},1,true))

来源：https://stackoverflow.com/questions/50057104/sum-of-all-number-combinations-excluding-repetition-excel

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excel

google-sheets

combinations