Bash script - “tar czf …” command ignore parameters

问题

I have a simple bash script called script.sh

!#/bin/bash
tar czf /var/log/apache2/Backup_$(date "+%d-%m-%Y").tar.gz /var/log/apache2/ --exclude='backup*' --exclude='Backup*'

When I rund this line in SSH-Console, all works fine but when I run the .sh-script at linux console with bash ./script.sh

then the tar czf ... command works but ignore the --exclude parameters

Whats wrong? I don't know... :/

回答1:

you have to use :

!#/bin/bash
tar -czf /var/log/apache2/Backup_`date "+%d-%m-%Y"`.tar.gz /var/log/apache2/ --exclude='backup*' --exclude='Backup*'

回答2:

try this one:

UPDATE

#!/bin/bash
tar  -cZf /var/log/apache2/Backup_$(date +%Y%m%d).tgz.gz /var/log/apache2/ --exclude='backup*' --exclude='Backup*'

exclude is a pattern... see these helps: help1 help2 help3

来源：https://stackoverflow.com/questions/22146246/bash-script-tar-czf-command-ignore-parameters