问题
Okay, I'm trying to achieve the following:
- C calls into rust
- rust calls back into c and registers a callback on a user defined trait object
- c calls into rust with the context
- rust calls the callback on the context (trait object)
I've been playing around with it quite a bit. I got quite far, but still not quite there.
The C bit:
#include <dlfcn.h>
#include <stdio.h>
void *global_ctx;
void c_function(void* ctx) {
printf("Called c_function\n");
global_ctx = ctx;
}
int main(void) {
void *thing = dlopen("thing/target/debug/libthing.dylib", RTLD_NOW | RTLD_GLOBAL);
if (!thing) {
printf("error: %s\n", dlerror());
return 1;
}
void (*rust_function)(void) = dlsym(thing, "rust_function");
void (*rust_cb)(void*) = dlsym(thing, "rust_cb");
printf("rust_function = %p\n", rust_function);
rust_function();
rust_cb(global_ctx);
}
The rust bit:
extern crate libc;
pub trait Foo {
fn callback(&self);
}
extern {
fn c_function(context: *mut libc::c_void);
}
pub struct MyFoo;
impl Foo for MyFoo {
fn callback(&self) {
println!("callback on trait");
}
}
#[no_mangle]
pub extern fn rust_cb(context: *mut Foo) {
unsafe {
let cb:Box<Foo> = Box::from_raw(context);
cb.callback();
}
}
#[no_mangle]
pub extern fn rust_function() {
println!("Called rust_function");
let tmp = Box::new(MyFoo);
unsafe {
c_function(Box::into_raw(tmp) as *const Foo as *mut libc::c_void);
}
}
The issue:
- My program segfaults when I try to call "callback" on the trait object in "rust_cb"
One Solution: - Change the function signature of "rust_cb" to
pub extern fn rust_cb(context: *mut MyFoo)
but that's not what I want, as I'm trying to create a safe wrapper that only knows the trait of the listener
Any help appreciated
PS: my assumption is that it segfaults, because the compiler doesn't know the offset of callback on the trait Foo, it needs the actual object to determine where it is. but then i have no idea how to work around that
回答1:
So, if you need to represent the Foo as a void *, you can use this:
extern crate libc;
pub trait Foo {
fn callback(&self);
}
extern {
fn c_function(context: *mut libc::c_void);
}
pub struct MyFoo;
impl Foo for MyFoo {
fn callback(&self) {
println!("callback on trait");
}
}
#[no_mangle]
pub extern fn rust_cb(context: *mut Box<Foo>) {
unsafe {
let cb: Box<Box<Foo>> = Box::from_raw(context);
cb.callback();
}
}
#[no_mangle]
pub extern fn rust_function() {
println!("Called rust_function");
let tmp: Box<Box<Foo>> = Box::new(Box::new(MyFoo));
unsafe {
c_function(Box::into_raw(tmp) as *mut Box<Foo> as *mut libc::c_void);
}
}
I think you may be misunderstanding what a trait object is. A trait object is a type that is the size of two pointers (so, 128 bits on a 64-bit system). In this example, Foo is not a trait object, it is a dynamically sized type (i.e. a type which has a variable size, such as str). Box<Foo> is a trait object. Box<Box<Foo>> is neither a trait object or a dynamically sized type, it is a type that has the same size as a pointer, which is why we need to use it here since we want to convert it into a void *.
I call it "leaking" because when you call Box::into_raw, you are leaking the memory of whatever is in the box, which means that that you are responsible for making sure the destructor (the Drop implementation) gets called.
回答2:
Rust trait objects such as Box<Foo> are double the size of a normal pointer, so you can't use void * to represent them. See std::raw::TraitObject for more information. Here is a working version of your code:
program.c:
#include <dlfcn.h>
#include <stdio.h>
struct rs_trait_obj {
void *data;
void *vtable;
};
struct rs_trait_obj global_ctx;
void c_function(struct rs_trait_obj ctx) {
printf("Called c_function\n");
global_ctx = ctx;
}
int main(void) {
void *thing = dlopen("thing/target/debug/libthing.dylib", RTLD_NOW | RTLD_GLOBAL);
if (!thing) {
printf("error: %s\n", dlerror());
return 1;
}
void (*rust_function)(void) = dlsym(thing, "rust_function");
void (*rust_cb)(struct rs_trait_obj) = dlsym(thing, "rust_cb");
printf("rust_function = %p\n", rust_function);
rust_function();
rust_cb(global_ctx);
}
lib.rs:
#![feature(raw)]
extern crate libc;
use std::raw::TraitObject;
use std::mem;
pub trait Foo {
fn callback(&self);
}
extern {
fn c_function(context: TraitObject);
}
pub struct MyFoo;
impl Foo for MyFoo {
fn callback(&self) {
println!("callback on trait");
}
}
#[no_mangle]
pub extern fn rust_cb(context: TraitObject) {
unsafe {
let cb: Box<Foo> = mem::transmute(context);
cb.callback();
}
}
#[no_mangle]
pub extern fn rust_function() {
println!("Called rust_function");
let tmp: Box<Foo> = Box::new(MyFoo);
unsafe {
c_function(mem::transmute(tmp));
}
}
This will only work on nightly rustc (because of the #![feature(raw)]) and will also give a warning because TraitObject isn't FFI-safe. If you want something that will work on stable, you can define some struct of an appropriate size like this and use it instead of TraitObject:
#[repr(C)]
struct FFITraitObject {
data: usize,
vtable: usize,
}
Another option, of course, would just be to use Box<Foo> in place of TraitObject, but then you would still get a warning:
extern crate libc;
pub trait Foo {
fn callback(&self);
}
extern {
fn c_function(context: Box<Foo>);
}
pub struct MyFoo;
impl Foo for MyFoo {
fn callback(&self) {
println!("callback on trait");
}
}
#[no_mangle]
pub extern fn rust_cb(context: Box<Foo>) {
context.callback();
}
#[no_mangle]
pub extern fn rust_function() {
println!("Called rust_function");
let tmp: Box<Foo> = Box::new(MyFoo);
unsafe {
c_function(tmp);
}
}
If you really want to use a void *, you could consider leaking the TraitObject as well as the MyFoo and use two levels of indirection.
来源：https://stackoverflow.com/questions/33929079/rust-ffi-passing-trait-object-as-context-to-call-callbacks-on